Molly bought a flat. At the beginning of

In this case we need to determine the significance of the claim made by the phone manufacturer, that the battery life of the new touch screen phone is more than twice as long as that of the leading product.

The information provided is:

$\bar x=10.5\\s=1.8\\n=45$

(a)

The hypothesis can be defined as follows:

H₀: The battery life of the new touch screen phone is not more than 10 hours, i.e. μ ≤ 10.

Hₐ: The battery life of the new touch screen phone is more than 10 hours, i.e. μ > 10.

(b)

As the population standard deviation is not provided, we will use a t-test for single mean.

Compute the test statistic value as follows:

$t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{10.5-10}{1.8/\sqrt{45}}=1.86$

The test statistic value is 1.86.

(c)

The significance level of the test is, α = 0.10.

The degrees of freedom will be:

$df=n-1=45-1=44$

Compute the critical value as follows:

$t_{0.10, 44}=1.301$

*Use a t-table for the value.

Thus, the critical value to test the phone manufacturer's claim is 1.301.

(d)

Decision rule:

If the test statistic value is less than the critical value then the null hypothesis will be rejected and vice-versa.

t = 1.86 > t₀.₁₀, ₄₄ = 1.30

The calculated t-value of the test is more than the critical value.

The null hypothesis will not be rejected.

Thus, it can be concluded that the battery life of the new touch screen phone is not more than 10 hours.

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Chris worked 45 hours at the library last week. If he gets time and a half for overtime and his

tia_tia [17]

The answer is c. I had to do this one on a test and the teacher put this one on the bored

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