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3 years ago

Which of the following objects is in dynamic equilibrium?

Physics

1 answer:

Vera_Pavlovna [14]3 years ago

5 0

a. A car driving in a straight line at 20 m/s.

Explanation:

An object is in a state of equilibrium when no force is acting upon it. There are two types of equilibrium; static equilibrium and dynamic equilibrium.

Static equilibrium is a state when a body is at rest.

Dynamic equilibrium is an equilibrium state when a body is moving at a constant velocity. (Rectilinear Motion).

A car moving in a straight line at 20 m/s has a constant velocity and hence no force is acting on it. So, it is in dynamic equilibrium.

A book sitting on a table without moving is not is dynamic equilibrium but in static equilibrium.

A boy jumping off a diving board in not in equilibrium as gravitational force is acting upon him and he has a changing velocity.

A motorcycle going in a circle at a constant speed has changing velocity because the direction of the motion is constantly changing hence it is not in the state of motion.

Keywords: velocity, force, equilibrium, static equilibrium, dynamic equilibrium

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3 years ago

When an object moves, where does the energy come from?

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3 years ago

A 5.0-μC charge is placed at the 0 cm mark of a meter stick and a -4.0 μC charge is placed at the 50 cm mark. At what point on a

Maksim231197 [3]

Answer:

The distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

Explanation:

Given that

q₁ = 5 μ C

q₂ = - 4 μ C

The distance between charges = 50 cm

d= 50 cm

Lets take at distance x from the charge μ C ,the electrical field is zero.

That is why the distance from the charge - 4 μ C = 50 - x cm

We know that ,electric field is given as

$E=K\dfrac{q}{r^2}$

$K\dfrac{5\ \mu}{x^2}=K\dfrac{4\mu }{(50-x)^2}\\\\\dfrac{5}{x^2}=\dfrac{4 }{(50-x)^2}\\\\\\5(50-x)^2=4x^2\\(50-x)^2=0.8x^2\\\\50-x =0.89x\\\ x=\dfrac{50}{1.89}\ cm\\\\\\x=26.45\ cm\\$

Therefore the distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

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3 years ago

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zmey [24]

Answer:

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Explanation:

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3 years ago

A wire 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is fo

Alex787 [66]

Answer:

ρ = 1.6*10⁻⁸ Ω/m.

Explanation:

Applying Ohm's Law to the wire, assuming that it can be treated as a pure resistance, the resistance of the wire can be obtained as follows:

$R = \frac{V}{I} = \frac{9.11V}{36.0A} = 0.253 \Omega (1)$

At the same time, we know that there exists a relationship between the resistance, the resistivity ρ, the length L and the area A of the wire, that is given for the following expression:

$R = \rho* \frac{L}{A} (2)$

The area of the circular section of the wire, can be expressed as a function of the diameter d, as follows:

$A = \frac{\pi*d^{2} }{4} = \frac{\pi*(0.002m)^{2}}{4} = \pi*10e-6 (3)$

Replacing the left side of (2) by (1), and (3) on the right side, we can solve for the resistivity ρ as follows:

$\rho = \frac{R*A}{L} = \frac{0.253\Omega*\pi*10e-6}{50.0m} = 1.6e-8 \Omega/m$

ρ = 1.6*10⁻⁸ Ω/m

4 0

3 years ago