Violet light has a frequency of 7.26 × 1014 Hz and travels at a speed of 3.00 × 108 m/s.

Which letter represents the wavelength of the wave?

Evgesh-ka [11]

The greek letter λ (lamda) is used to represent the wavelength of the wave.

6 0

3 years ago

Pressure and volume changes at a constant temperature can be calculated using

V125BC [204]

Answer:

Option A, Boyle's law

Explanation:

The complete question is

Pressure and volume changes at a constant temperature can be calculated using

a. Boyle's law. c. Kelvin's law.

b. Charles's law. d. Dalton's law.

Solution

In Boyle’s law, the gas is assumed to be ideal gas and at constant temperature. With these two conditions fixed, Boyle’s established that volume of gas varies inversely with the absolute pressure.

The basic mathematical representation of this phenomenon is as follows -

$P \alpha \frac{1}{V}$

OR

$P = \frac{k}{V} \\PV = k$

Where P is the pressure of ideal gas, V is the volume and k is the constant of proportionality.

Hence, option A is correct

3 0

3 years ago

If you drop a bouncing ball from a height of 40 centimeters, explain why it can only bounce back up to a height of less than 40

iren2701 [21]

Answer:

Due to energy loss while collision ball will not reach to same height while if there is no energy loss then in that case ball will reach to same height

Explanation:

As we know that initially ball is held at height h = 40 cm

So here we can say that kinetic energy of the ball is zero and potential energy is given as

$U = mgH$

now when strike with the ground then its its fraction of kinetic energy is lost in form of other energies

So the ball will left rebound with smaller energy and hence it will reach to height less than the initial height

While if we assume that there is no energy loss during collision then in that case ball will reach to same height again

8 0

3 years ago

In a charming 19th-century hotel, an old-style elevator is connected to a counterweight by a cable that passes over a rotating d

melisa1 [442]

Answer:

2.38732 rpm

1.22625 rad/s²

163.292°

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration = $\frac{1}{8}g$

d = Diameter of wheel = 2 m

r = Radius of wheel = $\frac{d}{2}=\frac{2}{2}=1\ m$

v = Speed of elevator = 25 cm/s

Angular speed is given by

$\omega=\frac{v}{r}\\\Rightarrow \omega=\frac{0.25}{1}\\\Rightarrow \omega=0.25\ rad/s=0.25\times \frac{60}{2\pi}\\\Rightarrow \omega=2.38732\ rpm$

The angular speed of the wheel is 2.38732 rpm

Angular acceleration is given by

$\alpha=\frac{a}{r}\\\Rightarrow \alpha=\frac{\frac{1}{8}g}{r}\\\Rightarrow \alpha=\frac{\frac{1}{8}\times 9.81}{1}\\\Rightarrow \alpha=1.22625\ rad/s^2$