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algol [13]
3 years ago
8

Violet light has a frequency of 7.26 × 1014 Hz and travels at a speed of 3.00 × 108 m/s.

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
8 0

Answer:

what's the question

........

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What quantities determine the resistance of a piece of material? Choose all that apply.
bija089 [108]

Answer:

Option (a), (b) and (c)

Explanation:

The resistance of a conductor depends on the length of the conductor, area of crossection of the conductor and the nature of the conductor.

The formula for the resistance is given by

R = ρ x l / A

Where, ρ is the resistivity of the conductor, l be the length of the conductor and A be the area of crossection of the conductor.

So, It depends on the length, area and the type of material.

7 0
3 years ago
Only negative charges move<br><br> True<br><br> False
Flura [38]
The answer is False, pls. mark me the brainliest if I’m right. THX
7 0
3 years ago
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A 2-kg wheel rolls down the road with a linear speed of 15m/s. Find its trwansitional and rotational kinetic energies.​
Elza [17]

Answer:

The translational kinetic energy is 225 J

The rotational kinetic energy is 225 J

Explanation:

Given;

mass of the wheel, m = 2-kg

linear speed of the wheel, v = 15 m/s

Transnational kinetic energy is calculated as;

E = ¹/₂MV²

where;

M is mass of the moving object

V is the velocity of the object

E =  ¹/₂ x 2 x (15)²

E = 225 J

Rotational kinetic energy is calculated as;

E = ¹/₂Iω²

where;

I is moment of inertia

ω is angular velocity

E = \frac{1}{2} I \omega^2\\\\E = \frac{1}{2} *mr^2*(\frac{v}{r})^2\\\\E =  \frac{1}{2} *mr^2*\frac{v^2}{r^2} \\\\E =  \frac{1}{2}mv^2

E =  ¹/₂ x 2 x (15)²

E = 225 J

Thus, the translational kinetic energy is equal to rotational kinetic energy

6 0
3 years ago
Which is not true about the variables in the relationship F = ma?
tatuchka [14]

Answer:

A

Explanation:

Because D is definitely true and there is only one false sentence what means if that non of B or C is false because if one is false so other one needs to be too.

8 0
3 years ago
A droplet of pure mercury has a density of 13.6 g/cm3. What is the density of a sample of pure mercury that is 10 times as large
luda_lava [24]
A droplet of pure mercury has a density of 13.6 g/cm3. What is the density of a sample of pure mercury that is 10 times as large as the droplet?

Answer: In this case the density will remain constant for both droplets. The reason being that volume will not change the density of the material. The only way of changing it is by changing its state. If you increase the volume then the mass will also increase. Leaving the density the same.

I hope it helps, Regards.
6 0
3 years ago
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