Answer:
m = 236212 [kg]
Explanation:
The potential energy can be determined by means of the product of mass by gravity by height. In this way, we have the following equation.
where:
P = potential energy = 3360000000 [J]
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 1450 [m]
Now, we can clear the mass from the equation above:
![3360000000=m*9.81*1450\\m = 236212 [kg]](https://tex.z-dn.net/?f=3360000000%3Dm%2A9.81%2A1450%5C%5Cm%20%3D%20236212%20%5Bkg%5D)
Answer:
a) t = 4.16 s
b) x = 141.51 m
Explanation:
Given
v = 21.5 m/s
x0 = 52.0 m
a = 6.0 m/s²
a) Motorcycle
x = v0*t + (a*t²/2)
x = 21.5t + (6*t²/2)
x = 21.5t + 3t² <em>(I)</em>
Car
x = x0 + v0*t
x = 52 + 21.5t <em>(II)</em>
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then we can apply <em>I = II</em>
21.5t + 3t² = 52 + 21.5t
⇒ 3t² = 52
⇒ t = 4.16 s
b) We can use <em>I</em> or <em>II</em>, then
x = 52 + 21.5*(4.16)
⇒ x = 141.51 m
Answer: An Incident on Route 12 is presented here in a high quality paperback edition. This popular classic work by James H. Schmitz is in the English language, and may not include graphics or images from the original edition.
Explanation: I HOPE THAT HELPED
Explanation:
It is given that, Onur drops a basketball from a height of 10 m on Mars, where the acceleration due to gravity has a magnitude of 3.7 m/s².
The second equation of kinematics gives the relationship between the height reached and time taken by it.
Here, the ball is droped under the action of gravity. The value of acceleration due to gravity on Mars is positive.
We want to know how many seconds the basketball is in the air before it hits the ground. So, the formula is :
t is time taken by the ball to hit the ground
is initial speed of the ball
So, the correct option is (A).
Freezing (liquid to solid)
Deposition (gas to solid)
Condensation (gas to liquid)
All three of these state changes are a result of a energy loss. When considering energy loss it is best to think of situations where temperature has dropped. Less energy in the system results in less energy the substance is exposed to or has available.
