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3 years ago

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This action toward a family member may be taken if he or she has a chemical dependency. A. divorce B. bargaining C. intervention

D. abandonment

2 answers:

SVETLANKA909090 [29]3 years ago

6 0

<span>C. intervention
..........
:DD</span>

love history [14]3 years ago

5 0

Answer:

C. intervention

Explanation:

-Divorce is the process of legal separation of a married couple.

-Bargaining is the negotiation of terms in a transaction.

-Intervention is the process in which family and/or friends try to make a person that has an addiction or other medical condition to get help and treatment.

-Abandonment is to leave family members like spouse or children for a period of time or permanently without legal excuse.

According to these definitions and considering that a chemical dependency includes alcoholism and drugs addiction, the action that may be taken toward a family member if he or she has a chemical dependency is intervention.

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Which of the following BEST describes a body in equilibrium?

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$\textsf {\large{\underline { \underline {SOLUTION:-}}}}$

⇰Let O be the point of observation on the ground OX.

⇰Let A and B be the two positions of the jet.

$\bf➠Then, \angle XOA=60⁰ \: and \: \angle \: XOB=30⁰ \\ \\$

$\bf ➠Draw \: AL \perp \: OX \: and \: BM \perp \: OX \\ \\$

$\bf \:⇰ Let \: AL=BM=h \: meters. \\ \\$

$\bf \: ⇰ \: Speed \: of \: Jet = 720 \: km/hr\\$

$\bf = \huge( \small \: 720 \times \frac{5}{18} \huge) \small \: m / s\\$

$\bf = 200 \: m/s$

$\bf \:➥ Time \: taken \: to \: cover \: the \: distance \: AB=15 \: sec \\ \\$

$\bf➥ Distance \: covered =(speed×time) \\ \\$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf = (200 \times 15)m = 3000m \\ \\$

$\bf \therefore LM=AB=3000m \\ \\$

${ \bf \: ⇰ \: Let \: OL} = x \: \bf m \\ \\$

$\bf➥From \: right \: \triangle OLA, \: we \: have: \\$

$\bf \frac{OL}{AL} =cot \: 60⁰= \frac{1}{ \sqrt{3} } \implies \frac{x}{h} = \frac{1}{ \sqrt{3} } \\ \\$

$\bf \implies \: x = \frac{h}{ \sqrt{3} } \: \: \: \: \: \: \: ....(1) \\ \\$

$\bf \:➥ From \: right \: \triangle \: OMB,we \: have: \\$

$\bf\frac{OM}{BM} =cot30⁰= \sqrt{3} \\ \\$

$\bf \implies \: \frac{x + 3000}{h} = \sqrt{3} \\ \\$

$\bf[ \boxed{➯OM=OL+LM=OL+AB=(x+3000)m \: and \: BM=h \: m]}$

$\bf \implies \: x + 3000 = \sqrt{3} h \\$

$\bf \implies \: x = ( \sqrt{3} h - 3000) \: \: \: \: \: \: ....(2) \\$

⇰ Equating the value of x from (1) and (2),we get;

$\bf \: \sqrt{3} h - 3000 = \frac{h}{ \sqrt{3} } \\ \\$

$\implies \bf \: 3h - 3000 \sqrt{3} = h \\$

$\bf \implies \: 2h = (3000 \times \sqrt{3} ) = (3000 \times 1.762) \\$

$\bf \implies \: h = (3000 \times 0.866) = 2598 \\ \\$

$\bf \:➥ Hence \: ,the \: required \: height \: is \: \boxed{ \boxed{ \bf2598 \: m.}} \\ \\$

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