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3 years ago

Using a spring as an example, explain the compressions and rarefactions of a wave.

Chemistry

1 answer:

Vladimir [108]3 years ago

5 0

Answer:

Compressions are the parts where the coils are close together.

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Naturally occurring neon exists as three isotopes. 90.51% is ne-20 with a mass of 19.99 amu, 0.27% is ne-21 with a mass of 20.99

gregori [183]

The atomic mass of an element is the average relative mass of its atoms as compared with an atom of carbon-12 whose mass is taken as 12. In terms of percentages of different isotopes, the average atomic mass can be determined as follows: $A_{average}$ = ∑( $p_{i}$ X $A_{i}$ )/100. Where, $p_{i}$ is the percentage abundance of isotope with atomic number $A_{i}$ .

So, average atomic mass of neon = $\frac{(90.51 X 19.99) + (0.27 X 20.99) + (9.22 X 21.99)}{100}$ = 20.177 amu.

3 0

3 years ago

A chemist must dilute of aqueous aluminum chloride solution until the concentration falls to . He'll do this by adding distilled

marshall27 [118]

Answer:

0.257 L

Explanation:

The values missing in the question has been assumed with common sense so that the concept could be applied

Initial volume of the AICI3 solution $=23.1 \mathrm{mL}$

Initial Molarity of the solution $=833 \mathrm{mM}$

Final molarity of the solution $=75.0 \mathrm{mM}$

Final volume of the solution $=?$

From Law of Dilution, $M_{f} V_{f}=M_{i} V_{i}$

$\Rightarrow V_{f}=\frac{M_{i} V_{i}}{M_{f}}=\frac{833 \mathrm{mM} \times 23.1 \mathrm{mL}}{75.0 \mathrm{mM}}=256.564 \mathrm{mL}=0.256564 \mathrm{L}=0.257 L$

Final Volume of the solution $=0.257$

7 0

3 years ago

What is the mass of one mole of carbon-12?

velikii [3]

Answer:

Hello

12 grams

The mass of one mole of carbon-12 atoms is 12 grams.

Hope it helps You.....

Explanation:

4 0

3 years ago

Read 2 more answers

Convert the volume to its equivalent in milliliters. 14 μL= ? mL

Diano4ka-milaya [45]

0.014 is the answer

6 0

3 years ago

Read 2 more answers

2c+02=2CO2. The moles of co2 produced when 0.25 moles of O2 react is?

Sophie [7]

<h3>Answer:</h3>

$\displaystyle 0.5 \ mol \ CO_2$

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Moles
Compounds

<u>Stoichiometry</u>

Using Dimensional Analysis
Analyzing Reactions RxN

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2C + O₂ → 2CO₂

[Given] 0.25 moles O₂

[Solve] moles CO₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol O₂ → 2 mol CO₂

<u>Step 3: Stoichiometry</u>

[DA] Set up: $\displaystyle 0.25 \ moles \ O_2(\frac{2 \ mol \ CO_2}{1 \ mol \ O_2})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 0.5 \ mol \ CO_2$

7 0

2 years ago