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scoundrel [369]
2 years ago
10

Consider the anion whose charge is 2- and whose electron configuration is identical to argon. what is the symbol for this anion

Chemistry
1 answer:
AleksAgata [21]2 years ago
8 0

If the ion is negatively charged, anion, it means that it gains two electrons from its surroundings. The number of electrons of an argon (neutral atom) is 18. Two of the electrons in our anion is from the surrounding, so originally it only has 16 electrons.

In the periodic table, the 16th element is sulphur. The chemical symbol of sulphur is S. Thus, the anion is the negatively charged sulphur with chemical symbol of S2-. 

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maksim [4K]

Answer:

T = 525K    

Explanation:

The temperature of the two-level system can be calculated using the equation of Boltzmann distribution:

\frac{N_{i}}{N} = e^{-\Delta E/kT}  (1)

<em>where Ni: is the number of particles in the state i, N: is the total number of particles, ΔE: is the energy separation between the two levels, k: is the Boltzmann constant, and T: is the temperature of the system </em>         

The energy between the two levels (ΔE) is:

\Delta E = hck    

<em>where h: is the Planck constant, c: is the speed of light and k: is the wavenumber</em>      

\Delta E = 6.63\cdot 10^{-34} J.s \cdot 3\cdot 10^{8}m/s \cdot 4 \cdot 10^{4}m^{-1} = 7.96 \cdot 10^{-21}J  

Solving the equation (1) for T:

T = \frac{-\Delta E}{k \cdot Ln(N_{i}/N)}  

<em>With Ni = N/3 and k = 1.38x10⁻²³ J/K, </em><em>the temperature of the two-level system is:</em><em> </em>

T = \frac{-7.96 \cdot 10^{-21}J}{1.38 \cdot 10^{-23} J/K \cdot Ln(N/3N)} = 525K                                  

I hope it helps you!

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