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3 years ago

MgCl2(at)+Br2(l)=MgBr2(at)+Cl2(g) how do you write in a word equation

Chemistry

1 answer:

kotykmax [81]3 years ago

6 0

aqueous Magnesium Chloride reacts with liquid Bromide to form aqueous Magnesium Bromide and Chlorine gas

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A cubic box with sides of 20.0 cm contains 2.00 × 1023 molecules of helium with a root-mean-square speed (thermal speed) of 200

Anarel [89]

Answer:

1.133 kPa is the average pressure exerted by the molecules on the walls of the container.

Explanation:

Side of the cubic box = s = 20.0 cm

Volume of the box ,V= $s^3$

$V=(20.0 cm)^3=8000 cm^3=8\times 10^{-3} m^3$

Root mean square speed of the of helium molecule : 200m/s

The formula used for root mean square speed is:

$\mu=\sqrt{\frac{3kN_AT}{M}}$

where,

= root mean square speed

k = Boltzmann’s constant = $1.38\times 10^{-23}J/K$

T = temperature = 370 K

M = mass helium = $3.40\times 10^{-27}kg/mole$

$N_A$ = Avogadro’s number = $6.022\times 10^{23}mol^{-1}$

$T=\frac{\mu _{rms}^2\times M}{3kN_A}$

Moles of helium gas = n

Number of helium molecules = N = $2.00\times 10^{23}$

N = $N_A\times n$

Ideal gas equation:

PV = nRT

Substitution of values of T and n from above :

$PV=\frac{N}{N_A}\times R\times \frac{\mu _{rms}^2\times M}{3kN_A}$

$PV=\frac{N\times R\times \mu ^2\times M}{3k\times (N_A)^2}$

$R=k\times N_A$

$PV=\frac{N\times \mu ^2\times M}{3}$

$P=\frac{2.00\times 10^{23}\times (200 m/s)^2\times 3.40\times 10^{-27} kg/mol}{3\times 8\times 10^{-3} m^3}$

$P=1133.33 Pa =1.133 kPa$

(1 Pa = 0.001 kPa)

1.133 kPa is the average pressure exerted by the molecules on the walls of the container.

3 0

3 years ago

**PLEASE HELP WITH SCIENCE**

fgiga [73]

it has an electrons in a fixed path together on energy levels.

5 0

3 years ago

An oxide of aluminum contains 0.545 g of Al and 0.485 g of O. Find the empirical formula

uysha [10]

Answer:

The answer is: <u>Al2O3</u>

Explanation:

The data they give us is:

0.545 gr Al

0.485 gr O.

To find the empirical formula without knowing the grams of the compound, we find it per mole:

0.545 g Al * 1 mol Al / 27 g Al = 0.02 mol Al

0.485 g O * 1 mol O / 16 g O = 0.03 mol O

Then we must divide the results obtained by the lowest result, which in this case is 0.02:

0.02 mol Al / 0.02 = 1 Al

0.03 mol O / 0.02 = 1.5 O

Since both numbers have to give an integer, multiply by 2 until both remain integers:

1Al * 2 = 2Al

1.5O * 2 = 3O

Now the answer is given correctly:

Al2O3

8 0

3 years ago

Which types of atomic orbitals of the central atom mix to form hybrid orbitals in:<br> (d) SO₃²⁻?

makkiz [27]

sp3d2 hybridization has 1s, 3p and 2d orbitals, that undergo intermixing to form 6 identical sp3d2 hybrid orbitals. These 6 orbitals are directed towards the corners of an octahedron. They are inclined at an angle of 90 degrees to one another.

<h3>Which orbitals hybridize to form hybrid orbitals?</h3>

For each carbon, one 2s orbital and two 2p orbitals hybridize to form three sp2 orbitals. These hybridized orbitals align themselves in the trigonal planar structure. For each carbon, two of these sp orbitals bond with two 1s hydrogen orbitals through s-sp orbital overlap.

<h3 /><h3>What is sp3d2 hybridization?</h3>

Intermixing of one 's', three 'p' and two 'd' orbitals of almost same energy by giving six identical and degenerate hybrid orbitals is called sp3d2 hybridization. These six sp3d2 orbitals are arranged in octahedral symmetry by making 90° angles to each other.

Learn more about hybridization here:

<h3 /><h3>brainly.com/question/1604211</h3><h3 /><h3>#SPJ4</h3>

4 0

1 year ago

Rapport de laboratoire

Umnica [9.8K]

Answer:

Un rapport de laboratoire permet à une personne qui n'a pas réalisé l'expérience de comprendre le but du laboratoire, la procédure à suivre pour atteindre cet objectif ainsi que les résultats obtenus.

6 0

2 years ago