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Vladimir79 [104]
3 years ago
7

What is the domain or range of y = one-fourth x minus 6

Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

domain and range will be ( negative infinity, positive infinity

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X² +8x +15 ÷ x²+ 6x +5<br>​
sineoko [7]
<h3>⚘Refer to the attachment!</h3>

7 0
2 years ago
Can anyone help me ?
Kipish [7]

Answer:

8. 1

7. 9

____

6. 2

5. 2

4. 1

3. 18

2. 10000

1. 25

Step-by-step explanation:

According to the Order of Operations, if there are any <em>grouping symbols</em>, you take care of them first. Second, you deal with any <em>indices</em><em>,</em> roots, or <em>powers</em><em>.</em><em> </em>Third comes the evaluation of<em> </em><em>Division</em><em> </em><em>&</em><em> </em><em>Multiplication</em><em> </em>from left to right in the order of which you see them appear. The fourth and final step is the evaluation of <em>Subtraction</em><em> </em><em>&</em><em> </em><em>Addition</em><em> </em>from left to right in the order of which you see them appear.

** I was writing down ALL my writing down all my calculations up until a computer glitch caused my work to go <em>work-rupt</em><em>,</em><em> </em>if<em> </em>you<em> </em>know what I mean.

I apologize for the inconvenience, I hope this explanation helps you out alot, and as always, I am joyous to assist anyone at any time.

3 0
3 years ago
How do you solve this 2 step equation: 8+b/-4=5
Delicious77 [7]
I'm going to rewrite the equation assuming this is the correct form:
8 - \frac{b}{4} = 5&#10;\newline&#10;-8 + 8 - \frac{b}{4} = 5 - 8&#10;\newline&#10;(-4)\cdot -\frac{b}{4} = -3 \cdot (-4)&#10;\newline&#10;b = -12
3 0
2 years ago
-2 = 3у – 18 — 5y<br> Solve for y
larisa [96]
-2=-2y-18

2y=-18+2

2y=-16

Y=-8

8 0
3 years ago
Which of the following is equivalent to the expression below sqrt 8 - sqrt 72 + sqrt 50
mash [69]

Answer:

Step-by-step explanation:

\sqrt{8}-\sqrt{72}+\sqrt{50} These cannot combine the way they are. The rule for adding and subtracting radicals is really picky. Not only does the index have to be the same (the little number that is sitting outside in the bend of the radical {ours is a 2, which isn't usually there, but is instead understood to be a square root}), but the radicand, the expression under the square root (or cubed root, or fourth root, etc) has to the same as well. All of our radicals are square roots, so that's good, but the radicands are all different. The first one is an 8, the next one is a 72, and the last one is a 50. BUT if we can rewrite them by simplifying them and then the radicands are the same, we're in good shape.

Simplify by taking the prime factorization of each of those numbers.

8: 4*2 and 4 is a perfect square, so we'll stop there

72: 36*2 and 36 is a perfect square, so we'll stop there

50: 25*2 and 25 is a perfect square, so we'll stop there.

Now, rewrite each one of them in terms of their prime factorization:

\sqrt{4*2}-\sqrt{36*2}+\sqrt{25*2} and then pull out each perfect square as its root:

2\sqrt{2}-6\sqrt{2}+5\sqrt{2} and now all the radicands are the same, so we can add them to get

1\sqrt{2}  or simply  \sqrt{2}

6 0
2 years ago
Read 2 more answers
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