Answer: The correct answer is -297 kJ.
Explanation:
To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:
2SO3 —> O2 + 2SO2 (196 kJ)
Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.
Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:
SO3 —>1/2O2 + SO2 (98 kJ)
S + 3/2O2 —> SO3 (-395 kJ)
Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.
S + O2 —> SO2
Now, we must add the enthalpies together to get our final answer.
-395 kJ + 98 kJ = -297 kJ
Hope this helps!
Answer:
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Answer:
- <u><em>butylphenyl ether.</em></u>
Explanation:
The formula of the compound is:
- CH₃ - CH₂ - CH₂ - CH₂ - O - C₆H₅
1. The functional group is of the kind R - O - R', i.e. two alkyl groups each attached to one end of the oxygen atom. That means that the compound is an ether.
2. One group attached to the oxygen group is CH₃ - CH₂ - CH₂ - CH₂ - which has 4 carbons and is named butyl group.
3. The other group attached to the oxygen atom is C₆H₅ - which is derived from ciclohexane as is known as phenyl group.
4. Using the rule of naming the subtituents in alphabetical order, you name butyl first and phenyl second, so it is <u><em>butylphenyl ether.</em></u>
Transport of Na+ from a place of low concentration to a place of higher concentration. <u>This is the right answer.</u>
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The sodium-potassium pump is the most common and well-known example of active transport. At the cell membrane, the sodium-potassium pump moves 3 sodium ions out of the cell and two potassium ions into the cell per ATP. Examples of active transport include the uptake of glucose in the human intestine and the uptake of minerals and ions into the root hair cells of plants.
One of the greatest examples of active transport is the movement of calcium ions out of cardiomyocytes. Cells secrete proteins such as enzymes, antibodies, and various other peptide hormones. Amino acids are transported across the intestinal mucosa of the human intestine. The movement of ions or molecules across cell membranes to regions of a higher concentration is assisted by enzymes and requires energy.
Learn more about Active transport here:-brainly.com/question/25802833
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