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iren2701 [21]
3 years ago
13

.Put 8.4 x 10^-6 into standard notation.

Chemistry
1 answer:
Murrr4er [49]3 years ago
5 0

Answer:

.0000084

Explanation:

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Một hỗn hợp X gồm CH3OH; C2H5OH; phenol có khối lượng 28,9 gam phản ứng vừa hết với 100ml dung dịch NaOH 2M. Phần trăm theo khối
slavikrds [6]

Answer:

nNaOH = 0,2 mol

Trong hỗn hợp các chất đề bài cho chỉ có phenol tác dụng với NaOH

C6H5OH + NaOH → C6H5ONa + H2O

   0,2  ←     0,2 (mol)

⟹ mphenol = 0,2.94 = 18,8 gam

⟹  

%mC6H5OH=18,8/28,9 x100%= 65,05%

Explanation:

3 0
3 years ago
A reaction between 46 grams of sodium and 71 grams of chlorine formed table salt and heat.
vazorg [7]

Answer:

d. 117 grams

Explanation:

The mass of the table salt produced will be 117 grams.

Chemical reactions obey the law of conservation of mass. In this regard, matter is neither created nor destroyed in the course of a chemical reaction. It is expected that the mass of the reactants and products remain the same.

 The reaction expression:

         2Na + Cl₂  →   2NaCl

So, mass of sodium  = 46g

      mass of chlorine formed = 71g

Mass of NaCl  = 46 + 71 = 117g

7 0
3 years ago
ANSWER ASAP!
ludmilkaskok [199]

Answer:

whats the question so i can answer?

6 0
3 years ago
If the half life of a radioactive isotope is 1 day, then how much of the original isotope remains at the end of two days?
ikadub [295]

\huge{\color{magenta}{\fcolorbox{magenta}{black}{\huge{\color{white}{\fcolorbox{aqua}{black}{✿ᴀɴsᴡᴇʀ✿}}}}}}

25%

Explanation:

In a half life of a radioactive isotope is 1 day,it means it loses its half mass each day

We a formula for N half life

\sf  { \frac{1}{2} }^{n}

where n is the number of days

Here the isotope is kept for 2 days

so it's left over mass will be

\sf { (\frac{1}{2}) }^{2}  \\  \\  \\  \frac{1}{2}  \times  \frac{1}{2}  \\  \\  \sf  \frac{1}{4}

It's left over mass 1/4th of the original mass

Now, we need to find it's percentage by multiplying with 100

\sf  \frac{1}{4}  \times 100 \%\\  \\  \sf   \cancel\frac{100}{4} \% \\  \\  \sf 25\%

<u>So</u><u> </u><u>2</u><u>5</u><u>%</u><u> </u><u>mass</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>left</u><u> </u><u>after</u><u> </u><u>2</u><u> </u><u>day</u><u> </u><u>of</u><u> </u><u>half</u><u> </u><u>life</u><u> </u><u>radioactive</u><u> </u><u>isotope</u><u>.</u><u> </u>

8 0
2 years ago
Read 2 more answers
What is the pH difference of two samples if the concentration of [H+] ions is 1000-fold less in the second sample?
snow_tiger [21]
The correct answer is a. This is because the pH of a solution is defined as -log10(concentration of H+ ions). An inverse logarithmic scale such as this means that a solution with a lower concentration of H+ ions will have a higher pH than one with a higher concentration. Therefore we know that the pH of the second sample will be higher than the first.

Since the logarithmic scale has the base 10, a change by 1 on the scale is a consequence of multiplication/division of the H+ concentration by a factor of 10. As the scale is inverse, this means that a decrease of concentration by factor 1000 is equivalent to increasing the pH by (1000/10) = 3.
4 0
3 years ago
Read 2 more answers
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