Answer:
2.89
Explanation:
pH=-log(H+)
- Hope that helps! Please let me know if you need further explanation.
The given question is incomplete. The complete question is:
How much heat is produced when 24.8 g of
is burned in excess oxygen gas
Given:
ΔH= −802 kJ.
Answer: 1243.1 kJ
Explanation:
Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.
Given :
Amount of heat released on combustion of 1 mole of methane = 802 kJ kJ/mol
According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number
of particles.
1 mole of
weighs = 16 g
Thus we can say:
16 g of
on combustion releases heat = 802 kJ
Thus 24.8 g of
on combustion releases =
Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ
The answer is c :) i hope its the right answer
Markovnikov rule, in organic chemistry, a generalization, formulated by Vladimir Vasilyevich Markovnikov in 1869, stating that in addition reactions to unsymmetrical alkenes, the electron-rich component of the reagent adds to the carbon atom with fewer hydrogen atoms bonded to it, while the electron-deficient component ...