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viktelen [127]
2 years ago
15

How do scientists take instruments for measurement up to about 100,000 feet of

Chemistry
1 answer:
uranmaximum [27]2 years ago
4 0
Answer: b
can’t be weather balloons cuz they would pop.
satellites are used for different things
no jet










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EXPERIMENT: THE CABBAGE INDICATOR
Nikitich [7]

Answer:

EXPERIMENT: THE CABBAGE INDICATOR

Here are your goals for this lesson:

Use indicator for each substance to determine if substance is an acid or a base

Summarize results and the experimental method

You can use the natural indicator in red cabbage juice to determine which household liquids are acids or bases. If no change in the color of the cabbage juice takes place, the liquid is neither an acid nor base; it is neutral.

Acids and bases are opposites. When an acids and base are mixed, they neutralize each other. You can use an indicator to see the neutralized reaction. The cabbage juice will change color when the liquids are neutralized.

Online Lab

This video will demonstrate how an indicator, in this case, cabbage indicator, can be used to determine whether a solution is acidic or basic. As you watch the video, remember to record your data and observations to use to present your findings.

Compile a summary of your findings from this experiment. Include your hypothesis, observations, data, and conclusions. Be sure to answer the questions below as well as explaining the method and results.

r.

Explanation:

8 0
1 year ago
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What volume (in mL) of a 0.113 M NaCl solution contains 0.087 mol NaCl?
Helen [10]
Hello I a m s o m o n e I n t h e w o r l d
5 0
3 years ago
Why do objects cool down​
zhannawk [14.2K]

Answer:

wla dyan ang sagut ehh baka mali yan

7 0
3 years ago
Determine the density of gold if a 475.09g sample occupy a space of 24.6cm^3
Ira Lisetskai [31]

Answer:

The answer is

<h2>19.31 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of gold = 475.09g

volume = 24.6 cm³

The density of the gold is

density =  \frac{475.09}{24 .6}  \\  = 19.3126016...

We have the final answer as

<h3>19.31 g/cm³</h3>

Hope this helps you

6 0
3 years ago
Before we can analyze the alum crystal it is
dusya [7]

Answer: TRUE

Explanation:

3 0
3 years ago
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