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Mashutka [201]
3 years ago
10

As you (increase, decrease) in altitude, air pressure decreases.

Physics
1 answer:
Bingel [31]3 years ago
5 0

Answer:

as you increase in altitude, air pressure decreases

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A man 6 feet tall walks at a rate of 6 feet per second away from a light that is 15 feet above the ground.
Tems11 [23]

Answer:(a)10 ft/s

(b)4 ft/s

Explanation:

Given

height of light =15 feet

height of man=6 feet

\frac{\mathrm{d} x}{\mathrm{d} t}=6 ft/s

From diagram

\frac{15}{y}=\frac{6}{y-x}

5(y-x)=2y

3y=5x

differentiate both sides

3\times \frac{\mathrm{d} y}{\mathrm{d} t}=5\times \frac{\mathrm{d} x}{\mathrm{d} t}

Tip of shadow is moving at the rate of

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{5}{3}\times 6=10 ft/s

(b)rate at which length of his shadow  is changing

Length of shadow is y-x

differentiating w.r.t time

\frac{\mathrm{d} (y-x)}{\mathrm{d} t}=\frac{\mathrm{d} y}{\mathrm{d} t}-\frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} (y-x)}{\mathrm{d} t}=10-6=4 ft/s

7 0
3 years ago
use the distributive property to express 16+48. please explain if you can or work it out so I can see how you got your answer. t
Rom4ik [11]
(40+10)+(8+6)
Hope I helped you
6 0
3 years ago
Which atmospheric layer prevents meteoroids from reaching earth’s surface
Natalija [7]
Stratosphere because the atmosphere get denser
5 0
3 years ago
How does the current model of the atom differ from<br> j j thomas model
bixtya [17]
Jj thomas' model contained electrons. 

The current model contains a nucleus with electrons orbiting around it. :)
4 0
3 years ago
A tire measures 20 inches in diameter. How many revolutions will the tire have completed when it has traveled 100 yards? Express
Soloha48 [4]
<h2>Number of revolutions required to travel 100 yards is 57.</h2>

Explanation:

Diameter of tire,D = 20 inches

Perimeter of tire = πD

Perimeter of tire = π x 20 = 62.8 inches

Distance traveled = 100 yards

1 yard = 36 inches

Distance traveled = 100 x 36 = 3600 inches

In one revolution it travels 62.8 inches.

\texttt{No of revolutions = }\frac{3600}{62.8}\\\\\texttt{No of revolutions = }57.32\\\\\texttt{No of revolutions = }57

Number of revolutions required to travel 100 yards is 57.

8 0
3 years ago
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