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Marta_Voda [28]
3 years ago
9

How is circular motion different from variable motion?

Physics
1 answer:
s344n2d4d5 [400]3 years ago
6 0
Variable motion moves in all different directions, while circular motion can only move in one direction. They're alike because both circular and variable are both constant. Another way they're alike is that variable motion is used with transportation movements like cars, trucks, and buses. Circular motion can also be used with transportation like with wheels on cars, trucks, and buses. The last way the types motions are different is that the circular motion can't be stopped once it's going down hill, but variable can be stopped.<span> </span>
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A brass rod with a length of 1.22 m and a cross-sectional area of 2.19 cm2 is fastened end to end to a nickel rod with length L
GaryK [48]

Answer:

a) L₂ = 0.676 m

b) σ₁ = 2.28*10⁸ N/m²

σ₂ = 9.62*10⁸ N/m²

c) ε₁ = 0.00253678

ε₂ = 0.00457875

Explanation:

Given info

L₁ = 1.22 m

A₁ = 2.19 cm² = 2.19*10⁻⁴ m²

L₂ = ?

A₂ = 0.52 cm² = 0.52*10⁻⁴ m²

P = 5.00*10⁴ N

E₁ = 9*10¹⁰ N/m²

E₂ = 2.1*10¹¹ N/m²

In order to get the length L of the nickel rod if the elongations of the two rods are equal, we can say that

ΔL₁ = ΔL₂   ⇒  P*L₁/(A₁*E₁) = P*L₂/(A₂*E₂)

⇒  L₂ = A₂*E₂*L₁ / (A₁*E₁)

⇒  L₂ = (0.52*10⁻⁴ m²)*(2.1*10¹¹ N/m²)*(1.22 m) / (2.19*10⁻⁴ m²*9*10¹⁰ N/m²)

⇒  L₂ = 0.676 m

The stress in the brass rod is obtained as follows

σ₁ = P/A₁ ⇒ σ = 5.00*10⁴ N / 2.19*10⁻⁴ m² = 2.28*10⁸ N/m²

The stress in the niquel rod is obtained as follows

σ₂ = P/A₂ ⇒ σ = 5.00*10⁴ N / 0.52*10⁻⁴ m² = 9.62*10⁸ N/m²

The strain in the brass rod is obtained as follows

σ₁ = E₁*ε₁    ⇒   ε₁ = σ₁ / E₁

⇒   ε₁ = 2.28*10⁸ N/m² / 9*10¹⁰ N/m² = 0.00253678

The strain in the niquel rod is obtained as follows

σ₂ = E₂*ε₂    ⇒   ε₂ = σ₂ / E₂

⇒   ε₂ = 9.62*10⁸ N/m² / 2.1*10¹¹ N/m² = 0.00457875

3 0
3 years ago
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