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2 years ago

How is circular motion different from variable motion?

1 answer:

6 0

Variable motion moves in all different directions, while circular motion can only move in one direction. They're alike because both circular and variable are both constant. Another way they're alike is that variable motion is used with transportation movements like cars, trucks, and buses. Circular motion can also be used with transportation like with wheels on cars, trucks, and buses. The last way the types motions are different is that the circular motion can't be stopped once it's going down hill, but variable can be stopped.

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How much power is needed to lift a 20-kg object to a height of 4.0 m in 2.5 seconds?

4vir4ik [10]

Answer:

313.92w

Explanation:

Formula for power:

P=W/∆t = Fv

Givens:

m=20kg

∆y=4.0m

∆t=2.5s

a=9.81m/s²

In order to find power, we first need to solve for work.

W=Fd (force*displacement), f=mg

W=mg∆y

W=(20kg)(9.81m/s²)(4.0m)

W=784.8J

P=W/∆t

P=784.8J/2.5s

P=313.92 watts

5 0

2 years ago

Of all the planets in our solar system, Jupiter has the greatest gravitational strength. If a 1.5 kg pair of running shoes would

Andre45 [30]

Answer:

gₓ = 23.1 m/s²

Explanation:

The weight of an object is on the surface of earth is given by the following formula:

$W = mg$

where,

W = Weight of the object on surface of earth

m = mass of object

g = acceleration due to gravity on the surface of earth = strength of gravity on the surface of earth

Similarly, the weight of the object on Jupiter will be given as:

$W_{x} = mg_{x}$

where,

Wₓ = Weight of the object on surface of Jupiter = 34.665 N

m = mass of object = 1.5 kg

gₓ = acceleration due to gravity on the surface of Jupiter = strength of gravity on the surface of Jupiter = ?

Therefore,

$34.65 N = (1.5 kg)g_{x}$

$g_{x} = \frac{34.65 N}{1.5 kg}$

gₓ = 23.1 m/s²

7 0

3 years ago

In February 2004, scientists at Purdue University used a highly sensitive technique to measure the mass of a vaccinia virus (the

OlgaM077 [116]

Answer:

a) m_v = m_s (( $\frac{w_o}{w}$ )² - 1) , b) m_v = 1.07 10⁻¹⁴ g

Explanation:

a) The angular velocity of a simple harmonic motion is

w² = k / m

where k is the spring constant and m is the mass of the oscillator

let's apply this expression to our case,

silicon only

w₉² = $\frac{K}{m_s}$

k = w₀² m_s

silicon with virus

w² = $\frac{k}{m_s + m_v}$

k = w² (m_v + m_s)

in the two expressions the constant k is the same and q as the one property of the silicon bar, let us equal

w₀² m_s = w² (m_v + m_s)

m_v = ( $\frac{w_o}{w}$ )² m_s - m_s

m_v = m_s (( $\frac{w_o}{w}$ )² - 1)

b) let's calculate

m_v = 2.13 10⁻¹⁶ [( $\frac{20.4}{2.85}$ )² - 1)]

m_v = 1.07 10⁻¹⁴ g

4 0

3 years ago

A body with initial velocity 8.0 m/s moves along a straight line with constant acceleration and travels

Aleksandr [31]

Answer:

(a) The average velocity is 16 m/s

(b) The acceleration is 0.4 m/s^2

(c) The final velocity is 24 m/s

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity (or the speed) of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, final speed is calculated as follows:

$v_f=v_o+at\qquad\qquad [1]$

The distance traveled by the object is given by:

$\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]$

(a) The average velocity is defined as the total distance traveled divided by the time taken to travel that distance.

We know the distance is x=640 m and the time taken t= 40 s, thus:

$\displaystyle \bar v=\frac{x}{t}=\frac{640}{40}=16$

The average velocity is 16 m/s

Using the equation [1] we can solve for a:

$\displaystyle a=\frac{v_f-v_o}{t}$

$\displaystyle a= 2\frac{x-v_ot}{t^2}$

Since vo=8 m/s, x=640 m, t=40 s:

$\displaystyle a= 2\frac{640-8\cdot 40}{40^2}=0.4$

The acceleration is 0.4 m/s^2

(b) The final velocity is calculated by [1]:

$v_f=8+0.4\cdot 40$

$v_f=8+16=24$

The final velocity is 24 m/s

3 0

2 years ago

Which example best represents the use of creativity in a scientific inquiry

vova2212 [387]

From all the options listed, as seen in the picture attached, the example which best represents the use of creativity in a scientific inquiry is option D. i.e. developing a new way to extract a particular protein from tissue samples. Figuring out new methods and implementing them is what is called as creativity in scientific inquiry.

5 0

3 years ago

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