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Marta_Voda [28]
3 years ago
9

How is circular motion different from variable motion?

Physics
1 answer:
s344n2d4d5 [400]3 years ago
6 0
Variable motion moves in all different directions, while circular motion can only move in one direction. They're alike because both circular and variable are both constant. Another way they're alike is that variable motion is used with transportation movements like cars, trucks, and buses. Circular motion can also be used with transportation like with wheels on cars, trucks, and buses. The last way the types motions are different is that the circular motion can't be stopped once it's going down hill, but variable can be stopped.<span> </span>
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1. Which one of the following physical quantities is formed after dividing<br>mass by volume?​
aivan3 [116]

Answer:

xxxxx

Explanation:

Density is the mass of an object divided by its volume. Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a Volume (the same volume as 1 milliliter).

3 0
2 years ago
At a certain place, Earth's magnetic field has magnitude B =0.703 gauss and is inclined downward at an angle of 75.4° to the hor
Irina18 [472]

Answer:

The charge flows in coulombs is

dq=1.843x10^{-5}C

Explanation:

The current magnitude of current is given by the resistance and the induced Emf as:

I=N*\frac{dF}{Rdt}

\frac{dq}{dt}=\frac{dF}{Rdt}=dq=N*\frac{dF}{R}

dq=\frac{N*\beta*A*(Cos(\alpha_f)-Cos(\alpha_i}{R}

N=1300, \beta=0.703, A=\pi*r^2=\pi*0.10^2=0.01\pi m^2, R=99.4+202=301.4Ω

\alpha_f=14.6,\alpha_i=165.4

Replacing :

dq=\frac{1300*0.703x10^{-4}*0.01\pi*(0.9667-(-0.9667))}{202+99.4}

dq=1.843x10^{-5}C

5 0
3 years ago
A wave has a period of 2 seconds and a wavelength of 4 meters.Calculate its frequency and speed.
Lana71 [14]
F=l/t
f=4/2
f=2m/s

Hope this helps

3 0
3 years ago
Read 2 more answers
Need help will mark you the Brainliest
Hatshy [7]
The last one is correct (D)
8 0
2 years ago
In a fireworks display, a rocket is launched from the ground with a speed of 18.0 m/s and a direction of 51.0° above the horizon
Masja [62]

Answer:38.66 m

Explanation:

Given

launch angle \theta =51^{\circ}

launch velocity u=18 m/s

center of mass continue to travel its original Path so it center of mass will be at a distance of

R=\frac{u^2\sin 2\theta }{g}

R=\frac{18^2\sin 102}{9.8}

R=32.33 m

Center of mass will be at x=32.33 m

(b)if one of the piece will be at x=26  m then other will be at

x_{com}=\frac{m_1x_1+m_2x_2}{m_1+m_2}

x_{com}=\frac{\frac{m}{2}\cdot 26+\frac{m}{2}\cdot x_0}{\frac{m}{2}+\frac{m}{2}}

32.33=\frac{26+x_0}{2}

x_0=38.66 m

8 0
2 years ago
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