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abruzzese [7]
3 years ago
7

A light bulb has a voltage of 36 and a current of 8 A. Calculate the resistance of the light bulb

Physics
1 answer:
timurjin [86]3 years ago
4 0
R = U : I. U is in Voltage and I is in Ampère. That gives you R = 36 : 8 = 4,5 Ohm
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URGENT!!!!!!!<br><br> PLEASE HELP WITH THIS PHYSICS PROBLEM
Levart [38]

Explanation:

Let

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x_2 = distance traveled while decelerating

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x_1 = v_0t + \frac{1}{2}at^2 = \frac{1}{2}at^2

\:\:\:\:\:= \frac{1}{2}(2.5\:\text{m/s}^2)(30\:\text{s})^2

\:\:\:\:\:= 1125\:\text{m}

We need the velocity of the rocket after 30 seconds and we can calculate it as follows:

v = at = (2.5\:\text{m/s}^2)(30\:\text{s}) = 75\:\text{m/s}

This will be the initial velocity when start calculating for the distance it traveled while decelerating.

v^2 = v_0^2 + 2ax_2

0 = (75\:\text{m/s})^2 + 2(-0.65\:\text{m/s}^2)x_2

Solving for x_2, we get

x_2 = \dfrac{(75\:\text{m/s})^2}{2(0.65\:\text{m/s}^2)}

\:\:\:\:\:= 4327\:\text{m}

Therefore, the total distance x is

x = x_1 + x_2 = 1125\:\text{m} + 4327\:\text{m}

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3 0
3 years ago
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mars1129 [50]

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3 years ago
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fgiga [73]
The correct answer is:
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7 0
3 years ago
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