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abruzzese [7]
3 years ago
7

A light bulb has a voltage of 36 and a current of 8 A. Calculate the resistance of the light bulb

Physics
1 answer:
timurjin [86]3 years ago
4 0
R = U : I. U is in Voltage and I is in Ampère. That gives you R = 36 : 8 = 4,5 Ohm
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What is the definition of physical change
jeka94
They are used to separate mixtures into their component compounds but can no usually be used to deprecate compounds into chemical elements or simpler compounds
7 0
3 years ago
The musical tone a piano has a frequency of 346HZ and a wavelength of 1.3 M what is the speed of the sound
prohojiy [21]

Answer:

v= 449.8 m/s

Explanation:

Given data

Frequency=  346Hz

Wave length= 1.4m

The expression below is used to find the speed

v= f \lambda\\\\

substitute

v= 346*1.3\\\\v= 449.8 m/s

Hence the speed is v= 449.8 m/s

5 0
3 years ago
How much tension must a rope withstand if it is used to accelerate a 6526 kg car vertically upwards at 8.9 m/s^2?
ExtremeBDS [4]

Answer:

The value is T =  122036.2 \  N

Explanation:

From the question we are told that

     The mass of the car is  m  = 6526 \  kg

      The acceleration  is  a=  8.9 \  m/s^2

Generally the net force applied on the rope is mathematically represented as

          F_{net}   =  T -  W

Here W is the weight of the car which is evaluated as

         W =  m * g

=>      W =  6526  * 9.8

=>       W =  63954.8 \  N

Generally the net force can also be mathematically represented as

       F =  m * a

So

        m * a  =  T  -  63954.8

=>     6526  *  8.9 =  T  -  63954.8

=>      T =  122036.2 \  N

7 0
3 years ago
What kind of electromagnetic radiation has the shortest wavelength? The longest?
lutik1710 [3]

Answer:

gamma is shortest, radio waves are longest

8 0
3 years ago
Two carts, one of mass 2m and one of mass m, approach each other with the same speed, v. When the carts collide, they hook toget
Nikitich [7]

Answer:

<em>Second option</em>

Explanation:

<u>Linear Momentum</u>

The linear momentum of an object of mass m and speed v is

P=mv

If two or more objects are interacting in the same axis, the total momentum is

P_t=m_1v_1+m_2v_2+...

Where the speeds must be signed according to a fixed reference

The images show a cart of mass 2m moves to the left with speed v since our reference is positive to the right

P_1=-2mv

The second cart of mass m goes to the right at a speed v

P_2=mv

The total momentum before the impact is

P_t=-2mv+mv=-mv

The total momentum after the collision is negative, both carts will join and go to the left side

The first option shows both carts with the same momentum before the collision and therefore, zero momentum after. It's not correct as we have already proven

The third option shows the 2m cart has a positive greater momentum than the other one. We have proven the 2m car has negative momentum. This option is not correct either

The fourth option shows the two carts keep separated after the collision, which contradicts the condition of the question regarding "they hook together".

The second option is the correct one because the mass m_2 has a negative momentum and then the sum of both masses keeps being negative

3 0
4 years ago
Read 2 more answers
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