P₁ = 0.90 atm
V₁ = 50.0 mL
T₁ = 298 K
P₂ = 1 atm
T₂ = 273 K
V₂ = P₁ x V₁ x T₂ / T₁ x P₂
V₂ = 0.90 x 50.0 x 273 / 298 x 1
V₂ = 12285 / 298
V₂ = 41 mL
Answer (1)
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Baloon with 3 moles og oxygen at 1 atm.The temperature of the balloon is <u>4 Kelvin</u>.
An ideal gas is a theoretical gas composed of many randomly transferring factor particles that aren't difficult to interparticle interactions. the best gasoline idea is beneficial because it obeys the precise gas law, a simplified equation of country, and is amenable to evaluation under statistical mechanics.
An ideal gas is described as one for which both the extent of molecules and forces between the molecules are so small that they have got no effect at the behavior of the gas. The real gas that acts almost like a really perfect gasoline is helium. that is due to the fact helium, in contrast to maximum gases, exists as an unmarried atom, which makes the van der Waals dispersion forces as low as viable
Using the ideal gas equation:-
Given;
P₁ = 1 atm
V₁ = 100 L
n = 3
r = 8.314
T = PV/nR
= 1 × 100 / 3 × 8.314
= 4 K
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I can't give an exact answer if you do not provide any unit of concentration. The most common unit of concentration is molarity, which is the number of moles of solute over the number of liters solution. Say for example, the concentration of the solution is 0.1 M. To find the equivalent mass percentage, the solution is as follows:
The molar mass of Sr(NO₃)₂ is <span>211.63 g/mol.
(0.1 mol </span>Sr(NO₃)₂/ L solution)(211.63 g/mol)(1 L solution/ 1 kg solution)(1 kg/1000 g solution) * 100 = <em>2.12% Sr(NO₃)₂ solution</em>