Answer: S8(s) + 8O2(g) → 8SO2(g) ΔH = -2368 kJ a.
B.) ELECTROLYTE..............
Answer:
2.5×10⁶ s
Explanation:
From the question given above, the following data were obtained:
Rate constant (K) = 2.8×10¯⁷ s¯¹
Half-life (t½) =?
The half-life of a first order reaction is given by:
Half-life (t½) = 0.693 / Rate constant (K)
t½ = 0.693 / K
With the above formula, we can obtain the half-life of the reaction as follow:
Rate constant (K) = 2.8×10¯⁷ s¯¹
Half-life (t½) =?
t½ = 0.693 / K
t½ = 0.693 / 2.8×10¯⁷
t½ = 2.5×10⁶ s
Therefore, the half-life of the reaction is 2.5×10⁶ s
A large quantity if hydronium ions indicates an Arrhenius acid.
B is gas
The chemical element krypton is classed as a noble gas and a nonmetal.
Love you