11m/s Bc of the fact that he sees her running at 11m/s
        
             
        
        
        
Answer:
when a force is applied by one object to a second object, an equal and opposite force is applied back on the first object
Explanation:
 
        
             
        
        
        
We have that the magnitude of the gravitational force  is mathematically given as
f=6.377N
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Force</h3>
Question Parameters:
Earth exerts a 100 N gravitational force on a metal box. 
(Mass of the earth is 6e24 kg and radius of the earth is 6.4e6m.)
Generally the equation for the Gravitational mForce  is mathematically given as

f=6.377N
For more information on Force visit
brainly.com/question/26115859 
 
        
             
        
        
        
Complete question:
The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t³ , where the time tis in seconds. The
particle is momentarily at rest at t is:
Select one:
a. 9.3s
b. 1.3s
C. 0.75s
d.5.3s
e. 7.3s
Answer:
b. 1.3 s
Explanation:
Given;
position of the particle, x(t)=1 6t- 3.0t³ 
when the particle is at rest, the velocity is zero.
velocity = dx/dt
dx /dt = 16 - 9t²
16 - 9t² = 0
9t² = 16
t² = 16 /9
t = √(16 / 9)
t = 4/3
t = 1.3 s
Therefore, the particle is momentarily at rest at t = 1.3 s