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3 years ago

5. Susan exerted 400 newtons of force while pushing on a huge boulder. The boulder moved 0 meters. Calculate work.

Physics

1 answer:

Stells [14]3 years ago

4 0

Answer:

0 J

Explanation:

Work is the product of force and distance in the direction of force.

The formula is ; Work = Force * Distance

Given that :

Force = 400 N

Distance = 0 meters

Work = 400 * 0 = 0 J

No work was done because the boulder did not move.

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A robin in flight has 20.8 J of PE when it is 27.6 m high. What is the mass of the robin? (Unit = kg)

schepotkina [342]

Answer:

<h2> $\boxed{ \bold{ \purple{0.0769 \: kg \: }}}$ </h2>

Explanation:

$\sf{Potential Energy ( P.E ) \: = \: 20.8 \: joule}$

$\sf{distance \: = 27.6 \: metre}$

$\sf{mass = }$ ?

$\sf{acceleration \: due \: to \: gravity = 9.68 \: {metre \: per \: second}^{2} }$

Now, let's find the mass:

$\sf{PE \: = mass \times gravity \: \times \: distance}$

plug the values

⇒ $\sf{20.8 = m \times 9.8 \times 27.6}$

Multiply the numbers

⇒ $\sf{20.8 = 270.48 \: m}$

Swap the sides of the equation

⇒ $\sf{270.48m = 20.8}$

Divide both sides of the equation by 270.48

⇒ $\sf{ \frac{270.48m}{270.48} = \frac{20.8}{270.48} }$

Calculate

⇒ $\sf{0.0769}$ kg

Hope I helped!

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Samantha is viewing a real image formed by a lens of a diamond ring. Which must be true about the image?

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If a 10-volt battery is placed across a 2-ohm resistance (R = 20), a current of

attashe74 [19]

Answer: current I = 0.5 A

Explanation:

Given that the

Potential difference V = 10V

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According to ohms law

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3 years ago

What is the change in potential energy if the distance separating the electron and proton is increased to 1.0 nm?

Vlada [557]

Answer:

$Ep=-2.3*10^{-19}J$

Explanation:

The change in potential energy can be expressed as:

$Ep=K.\frac{q1.q2}{r}$

where K is a constant with a value of $9*10^{9}\frac{N.m^{2}}{C^{2}}$ , q1 and q2 are the charges of the proton and the electron and r is the distance between them.

The charge for the proton is $+1.6*10^{-19}C$ and the charge for the electron is $-1.6*10^{-19}C$ .

Converting r=1.0nm to m:

$1.0nm*\frac{1*10^{-9}m}{1.0nm}=1*10^{-9}m$

Replacing values:

$Ep=9*10^{9}\frac{N.m^{2}}{C^{2}}.\frac{(+1.6*10^{-19}C).(-1.6*10^{-19}C)}{1*10^{-9}m}$

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