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lana [24]
3 years ago
6

The expression known as​ Froude's number is given as Upper F equals StartFraction v squared Over gl EndFraction . This number wa

s used in shipbuilding and also in research on dinosaurs. In this​ example, l is given as well as​ Froude's number. Find the​ velocity, v​ (in meters per​ second) of a rhinoceros. It is known that gequals9.8 meters per second squared. ​Rhinoceros: lequals​ 1.2; Froude number equals 2.6
Physics
1 answer:
bearhunter [10]3 years ago
8 0

Answer:v=5.529\ m/s

Explanation:

Given

number is given as =\frac{v^2}{gl}

and number=2.6

l=1.2\ m

g=acceleration due to gravity(9.8\ m/s^2)

calculating for v

v^2=gl(2.6)

v=\sqrt{2.6\times 9.8\times 1.2}

v=\sqrt{30.576}

v=5.529\ m/s

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Use the accompanying seismogram to answer which of the three types of seismic waves reached the seismograph first.
UkoKoshka [18]

Answer:

Primary waves (P-waves)

Explanation:

Due to excess of the energy inside the earth when the tectonic plates begin to slide or fracture then the energy is released in the form of seismic waves, this causes the earthquake.

<u>Two types of seismic waves are generally responsible for the earth quakes:</u>

  1. body waves
  2. surface waves

Body waves are of two types:

Primary waves (P-waves)

These are the fastest of all the waves involved in the earth-quake which travel at a speed of 1.6 km to 8 km per second.

They can pass trough solids, liquids and gases. They arrive at the surface as an instant thud.

Secondary waves (S-waves)

They can only pass through the solids and they move slower than the P-waves.

As S-waves move, they displace the rock particles, pushing them outwards perpendicular to the wave-path that leads to the earthquake-related first rolling period.

Surface waves (L-waves/ long waves)

  • These waves move along the surface of the earth. They are responsible for the earthquake's carnage.
  • They move up and down the Earth's surface, rocking the foundations of man-made structures.
  • Surface waves are slowest of the three waves, which means that they are the last to arrive. So at the end of an earthquake usually comes the most powerful shaking.
6 0
2 years ago
What is the second law of thermodynamics
andriy [413]
It states that the total entropy of an isolated system can never decrease over time
5 0
2 years ago
What are the variables of Boyle's law?
vesna_86 [32]

Answer: pressure and volume

Explanation:

Boyle's law states that the volume of a fixed mass of gas is inversely proportional to the pressure of the gas provided temperature is kept constant.

Mathematically, Boyle's law can be explained as: PV = k,

where P is pressure

V is volume, and

k is a constant.

So, increase in the pressure of a gas leads to decrease in its volume and vice versa.

3 0
3 years ago
A parallel combination of a 1.13-μF capacitor and a 2.85-μF one is connected in series to a 4.25-μF capacitor. This three-capaci
Nata [24]

Answer:

(a) Charge of 4.25 μF capacitor is 35.46 μC.

(b) Charge of 1.13 μF capacitor is 10.05 μC.

(c) Charge of 2.85 μF capacitor is 25.36 μC.

Explanation:

Let C₁ , C₂ and C₃ are the capacitor which are connected to the battery having voltage V. According to the problem, C₁ and C₂ are connected in parallel. There equivalent capacitance is:

C₄ = C₁ + C₂

Substitute 1.13 μF for C₁ and 2.85 μF for C₂ in the above equation.

C₄ = ( 1.13 + 2.85 ) μF = 3.98 μF

Since, C₄ and C₃ are connected in series, there equivalent capacitance is:

C₅ = \frac{C_{3}C_{4}  }{C_{3} + C_{4}  }

Substitute 4.25 μF for C₃ and 3.98 μF for C₄ in the above equation.

C₅ = \frac{4.25\times3.98 }{4.25 + 3.98  }

C₅ = 2.05 μF

The charge on the equivalent capacitance is determine by the relation :

Q = C₅ V

Substitute 2.05 μF for C₅ and 17.3 volts for V in the above equation.

Q = 2.05 μF x 17.3  = 35.46 μC

Since, the capacitors C₃ and C₄ are connected in series, so the charge on these capacitors are equal to the charge on the equivalent capacitor C₅.

Charge on the capacitor, C₃ = 35.46 μC

Charge on the capacitor, C₄ = 35.46 μC

Voltage on the capacitor C₄ = \frac{Q}{C_{4} } = \frac{35.46\times10^{-6} }{3.98\times10^{-6}} = 8.90 volts

Since, C₁ and C₂ are connected in parallel, the voltage drop on both the capacitors are same, that is equal to 8.90 volts.

Charge on the capacitor, C₁ = C₁ V = 1.13 μF x 8.90 = 10.05 μC

Charge on the capacitor, C₂ = C₂ V = 2.85 μF x 8.90 = 25.36 μC

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3 years ago
"The two equations below express conservation of energy and conservation of mass for water flowing from a circular hole of radiu
Leno4ka [110]

Answer:

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