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lana [24]
3 years ago
6

The expression known as​ Froude's number is given as Upper F equals StartFraction v squared Over gl EndFraction . This number wa

s used in shipbuilding and also in research on dinosaurs. In this​ example, l is given as well as​ Froude's number. Find the​ velocity, v​ (in meters per​ second) of a rhinoceros. It is known that gequals9.8 meters per second squared. ​Rhinoceros: lequals​ 1.2; Froude number equals 2.6
Physics
1 answer:
bearhunter [10]3 years ago
8 0

Answer:v=5.529\ m/s

Explanation:

Given

number is given as =\frac{v^2}{gl}

and number=2.6

l=1.2\ m

g=acceleration due to gravity(9.8\ m/s^2)

calculating for v

v^2=gl(2.6)

v=\sqrt{2.6\times 9.8\times 1.2}

v=\sqrt{30.576}

v=5.529\ m/s

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The muzzle velocity of a 50.0g shell leaving a 3.00 kg rifle is 400m/s what is the recoil velocity of the rifle
serg [7]

Here if we consider bullet and gun as a system then we can say that momentum of the system will remain conserved

so we will have

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

now we know that

m_1 = 50 g = 0.050 kg

m_2 = 3 kg

v_{1i} = v_{2i} = 0

v_{1f} = 400 m/s

now we will have

0.050(0) + 3(0) = 0.050(400) + 3(v)

20 + 3v = 0

v = - \frac{20}{3} = - 6.67 m/s

so gun will recoil with speed 6.67 m/s

6 0
3 years ago
A 600kg car is at rest , and then accelerates to 5n/s what is the original kinetic energy?
lubasha [3.4K]
M = 600 kg
u = 0 (as the car was at rest initially)
v = 5 m/s
Initial kinetic energy = ½mu²
= ½×600×0
= 0
Final kinetic energy = ½mv²
= ½×600×25
= 7500 J
7 0
3 years ago
Select all that apply.
Ira Lisetskai [31]
A = false, it will take 0.031 cal to raise 1g Au 1degree while it will take 0.033 cal to raise 1g Hg 1 degree so, although Au will heat up faster, it will not be discernably faster so...
b = true
c = false, Au density > Hg
d = true
7 0
3 years ago
Read 2 more answers
A spring with an 8-kg mass is kept stretched 0.4 m beyond its natural length by a force of 32 N. The spring starts at its equili
pentagon [3]

Answer:

x = 1.26 sin 3.16 t

Explanation:

Assume that the general equation of the displacement given as

x = A sinω t

A=Amplitude ,t=time ,ω=natural frequency

We know that speed V

V=\dfrac{dx}{dt}

V= A ω cosωt

Maximum velocity

V(max)= Aω

Given that F= 32 N

F = K Δ

K=Spring constant

Δ = 0.4 m

32 =0.4 K

K = 80 N/m

We know that  ω²m = K

8 ω² = 80

ω = 3.16 s⁻¹

Given that V(max)= Aω = 4 m/s

3.16 A = 4

A= 1.26 m

Therefore the general equation of displacement

x = 1.26 sin 3.16 t

7 0
3 years ago
Read 2 more answers
What is the velocity of a beam of electrons that goes undeflected when passing through perpendicular electric and magnetic field
goldenfox [79]
F = qE + qV × B
where force F, electric field E, velocity V, and magnetic field B are vectors and the × operator is the vector cross product. If the electron remains undeflected, then F = 0 and E = -V × B
which means that |V| = |E| / |B| and the vectors must have the proper geometrical relationship. I therefore get
|V| = 8.8e3 / 3.7e-3
= 2.4e6 m/sec
Acceleration a = V²/r, where r is the radius of curvature.
a = F/m, where m is the mass of an electron,
so qVB/m = V²/r.
Solving for r yields
r = mV/qB
= 9.11e-31 kg * 2.37e6 m/sec / (1.60e-19 coul * 3.7e-3 T)
= 3.65e-3 m
6 0
3 years ago
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