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Thepotemich [5.8K]
3 years ago
14

How many constellations does the international astronomical union recognize?

Physics
1 answer:
Aliun [14]3 years ago
3 0

The answer is 88 the international astronomical union recognized 88 constellations in the sky

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Which statement best describes the atoms of elements that form compounds by covalent bonding?
k0ka [10]

Answer:

they share electrons between them.

Explanation:

taking the test rn lol i think its right

4 0
3 years ago
What are the frequencies of EM spectrum
kap26 [50]

The EM spectrum has no limits.  Any frequency you can imagine
is the frequency of some electromagnetic radiation somewhere.


3 0
3 years ago
How many times farther is Proxima Centauri from the sun than is earth from the sun
Aleks04 [339]

Answer:

Of the three stars in the system, the dimmest - called Proxima Centauri - is actually the nearest star to the Sun. The two bright stars, called Alpha Centauri A and B form a close binary system; they are separated by only 23 times the Earth - Sun distance.

5 0
3 years ago
Read 2 more answers
If a particle undergoes shm with amplitude 0.21 m, what is the total distance it travels in one period?
Ymorist [56]
If a particle undergoes simple harmonic motion with an amplitude of 0.21 meters, this means that the maximum displacement of the particle from its resting position is 0.21. For one period, it traveled from its starting position which is twice the amplitude and then back to its original position which is another distance that is twice the amplitude as well. Therefore, the total distance it traveled is 2*amplitude + 2*amplitude = 2*0.21 + 2*0.21 = 0.42 + 0.42 = 0.84 meters.
7 0
3 years ago
3.00 m^3 of water is at 20.0°C.
romanna [79]

Answer:

\triangle V = 0.02484m^3

Explanation:

Given

V_1 = 3.00m^3 --- initial volume

T_1 = 20.0^oC --- initial temperature

T_2 = 60.0^oC --- final temperature

\gamma = 207*10^{-6 ---  coefficient of thermal expansion:

Required

The change in volume

To do this, we make use of cubic expansivity formula

\triangle V = \gamma * V_2 * (T_2 - T_1)

So, we have:

\triangle V = 207 * 10^{-6} * 3.00 * (60.0 - 20.0)

\triangle V = 207 * 10^{-6} * 3.00 * 40.0

\triangle V = 0.02484m^3

The volume will expand by 0.02484m^3

7 0
2 years ago
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