Answer:
0.84 s
Explanation:
Step 1
Given information:
Mass of the ice (m) = 2.0 kg
Heat transfer rate (Q/T) = 793.0 kW
Latent heat of fusion of ice (Lf) = 334 kJ/kg
Substituting the corresponding values we have:
Answer:
A. No
B. si
Explanation:
A. El trabajo realizado en la carga es la energía potencial ganada por la carga al elevar la carga al nivel del camión y colocar la carga dentro del camión.
El trabajo realizado para elevar la carga W = m × g × h
Dónde;
m = masa de la carga
g = aceleración debido a la gravedad
h = Nivel de altura donde se coloca la carga en el camión
Por lo tanto, el trabajo realizado depende de la masa, m, de la carga y el nivel de altura, h, donde la carga se coloca en el camión y el trabajo realizado es el mismo para todos los métodos utilizados para colocar la carga en el camión
B. La ecuación para el trabajo realizado, W, también se puede escribir de la siguiente manera;
W = Fuerza, F × Distancia, D
De lo que tenemos;
F = W/D
Por lo tanto, cuando la mesa aumenta la distancia, como una rampa o un plano inclinado, la fuerza requerida disminuirá.
Answer:
<h3>Vab=Va-Vb</h3><h3>Vab=Vb-Va</h3><h3>
Explanation:</h3>
Vab is velocity of a relative to b
Vba is velocity of b relative to a
Explanation:
The somatic nervous system coordinates the voluntary control of movement in the body system.
The nervous system is made up of the central nervous system and peripheral nervous system.
The peripheral nervous system is made up of the nerves that branches into the body from the spinal cord.
- It consist of the somatic nervous system and the autonomous nervous system.
- The somatic nervous system controls the voluntary actions of movement in the body.
- It coordinates the reflex arc.
Learn more:
Nervous system brainly.com/question/4662759
#learnwithBrainly
Answer:
I = 1.06886 N s
Explanation:
The expression for momentum is
I = F t = Δp
therefore the momentum is a vector quantity, for which we define a reference system parallel to the floor
Let's find the components of the initial velocity
sin 28.2 = v_y / v
cos 28.2= vₓ / v
v_y = v sin 282
vₓ = v cos 28.2
v_y = 42.8 sin 28.2 = 20.225 m / s
vₓ = 42.8 cos 28.2 = 37.72 m / s
since the ball is heading to the ground, the vertical velocity is negative and the horizontal velocity is positive, it can also be calculated by making
θ = -28.2
v_y = -20.55 m / s
v_x = 37.72 m / s
X axis
Iₓ = Δpₓ = 
since the ball moves in the x-axis without changing the velocity, the change in moment must be zero
Δpₓ = m 
- m v₀ₓ = 0
v_{fx} = v₀ₓ
therefore
Iₓ = 0
Y axis
I_y = Δp_y = p_{fy} -p_{oy}
when the ball reaches the floor its vertical speed is downwards and when it leaves the floor its speed has the same modulus but the direction is upwards
v_{fy} = - v_{oy}
Δp_y = 2 m v_{oy}
Δp_y = 2 0.0260 (20.55)
= 1.0686 N s
the total impulse is
I = Iₓ i ^ + I_y j ^
I = 1.06886 j^ N s
