(Please help asap)

When the temperature of a metal cylinder is raised from 0.0°C to 110°C, its length increases by 0.22%. Find the percent change i

monitta

<span>Volume of cylinder = pi*r*2*L

As, from the above formula,volume is directly proportional to length,
So, if we increase in length also increases in volume by 0.22%

we know

</span><span>density=<span><span>mass/</span><span>volume

As, density is inversely proportional to volume it means increasing in volume decreases the density by 50.22%
</span></span></span>

8 0

3 years ago

Read 2 more answers

A charge of 0.91 C is spread uniformly throughout a 25 cm rod of radius 4 mm. What are the volume and linear charge densities

Oxana [17]

The volume of the rod is 1.26×10⁻⁵ m³, and the linear charge density of the rod is 3.64 C/m

<h3>What is volume?:</h3>

This is the product of the height of a solid object and its crossectional area.

The Volume of the rod is can be calculated using the formula below.

Note: A rod has the shape of a cylinder.

Formula:

V = πr²h............... Equation 1

Where:

V = Volume of the rod
r = radius of the rod
h = height of the rod.

From the question,

Given:

r = 4mm = 0.004 m
h = 25 cm = 0.25 m
π = 3.14

Substitute these values into equation 1

V = 3.14(0.004²)(0.25)
V = 1.26×10⁻⁵ m³

<h3>What is linear charge density:</h3>

This is the ratio of the charge on an object to the length of the object.

The linear charge density of the rod can be calculated using the formula below.

D = Q/h.................... Equation 2

Where:

D = Linear charge density of the rod
Q = Charge on the rod.
h = height or length of the rod

From the question

Given:

Q = 0.91 C
h = 25 cm = 0.25 m

Substitute these values into equation 2

D = 0.91/0.25
D = 3.64 C/m

Hence, The volume of the rod is 1.26×10⁻⁵ m³, and the linear charge density of the rod is 3.64 C/m

Learn more about charge density here: brainly.com/question/14568868

4 0

2 years ago

PLEASE HELP ASAP THANK YOU You're out for run. Your initial velocity is 1.5 m/s. Suddenly a crazy dog starts chasing you and you

Cerrena [4.2K]

Answer:

Your displacement would be

s = 22.5 m

s=1/2(v+u)t

5 0

3 years ago

Copper has a modulus of elasticity of 110 GPa. A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm is pull

bearhunter [10]

Answer:

$strain = 1.4 \times 10^{-3}$

Explanation:

As we know by the formula of elasticity that

$E = \frac{stress}{strain}$

now we have

$E = 110 GPA$

$E = 110 \times 10^9 Pa$

Area = 15.2 mm x 19.1 mm

$A = 290.3 \times 10^{-6}$

now we also know that force is given as

$F = 44500 N$

here we have

stress = Force / Area

$stress = \frac{44500}{290.3 \times 10^{-6}}$

$stress = 1.53 \times 10^8 N/m^2$

now from above formula we have

$strain = \frac{stress}{E}$

$strain = \frac{1.53 \times 10^8}{110 \times 10^9}$

$strain = 1.4 \times 10^{-3}$

7 0

3 years ago

A light ray in air enters and passes through a block of glass. What can be stated with regard to its speed after it emerges from

Furkat [3]

A light ray in air enters and passes through a block of glass , the speed will remain same after it emerges from the block

When a light ray enters into the glass then the speed of the light will get decreased because as a light ray enters into a denser medium , the speed of light get decreased . But when the light ray emerges out from glass , it going from denser to rarer medium , due to which speed will increase and come to same value as it was while entering the glass .

To learn more about denser medium here :

brainly.com/question/13613040

#SPJ4

3 0

1 year ago