-- Take a straight ruler.
-- Lay it down with the 'zero' mark at the start point.
-- Rotate it around the start point until the end point is also touching the edge of the ruler.
-- From the marks on the ruler, read the straight-line distance from the start point to the end point.
-- Without moving the ruler, observe and write down the DIRECTION from the start point to the end point.
-- The Displacement is the straight-line distance and direction from the start point to the end point.
Vector 1 has components
and vector 2 has
Add these vectors to get the resultant, which has components
The magnitude of the resultant is
with direction 
such that
or about 50º N of E.
By studying meteorites which are the most ancient material in space.
<span>The top benefit of pesticides is their effectiveness against pests that would otherwise decimate crops large and small. </span>
The distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.
<h3>Distance from the center of the meter rule</h3>
The distance from the centre of the rule at which a 2N weight must be suspend from A is calculated as follows;
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20 A (30 - x)↓ x ↓ 20 cm B 30 cm
2N 0.9N
Let the center of the meter rule = 50 cm
take moment about the center;
2(30 - x) + 0.9(x)(30 - x) = 0.9(20)
(30 - x)(2 + 0.9x) = 18
60 + 27x - 2x - 0.9x² = 18
60 + 25x - 0.9x² = 18
0.9x² - 25x - 42 = 0
x = 29.3 cm
Thus, the distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.
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