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arlik [135]
3 years ago
8

Sweating and panting are examples of which characteristics of life?

Physics
2 answers:
Marianna [84]3 years ago
7 0
C.reproducing is think and if wrong I'm so very sorry
Debora [2.8K]3 years ago
3 0
B. using energy.    using alot of energy, like for exercising causes sweating and panting
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• The average length is ________ cm. This is the mean or average. b)• Subtract the highest value from the lowest value: ________
coldgirl [10]
16, 5 , 3 = 16+5+3= 24 + 3

So at the end put 24 + 3 cm
And put 16 for the lengths
For the value 5 and for the diving thingy 3
7 0
3 years ago
Football is kicked at 23.4 m/s at a 38.5 angle. How far away does it land?
natulia [17]

Answer: go0gle will know the answer

Explanation: hey I’m not giving fault answers so yea

5 0
2 years ago
Read 2 more answers
Why do objects repel and attract?
Anarel [89]
Objects repel and attract because of a thing called electrostatic attraction. When objects have the same charge (positive or negative), then they will repel, and if they have opposite charges then they will attract
5 0
3 years ago
Please help. I don’t understand this
skad [1K]

The short answer is that the displacement is equal tothe area under the curve in the velocity-time graph. The region under the curve in the first 4.0 s is a triangle with height 10.0 m/s and length 4.0 s, so its area - and hence the displacement - is

1/2 • (10.0 m/s) • (4.0 s) = 20.00 m

Another way to derive this: since velocity is linear over the first 4.0 s, that means acceleration is constant. Recall that average velocity is defined as

<em>v</em> (ave) = ∆<em>x</em> / ∆<em>t</em>

and under constant acceleration,

<em>v</em> (ave) = (<em>v</em> (final) + <em>v</em> (initial)) / 2

According to the plot, with ∆<em>t</em> = 4.0 s, we have <em>v</em> (initial) = 0 and <em>v</em> (final) = 10.0 m/s, so

∆<em>x</em> / (4.0 s) = (10.0 m/s) / 2

∆<em>x</em> = ((4.0 s) • (10.0 m/s)) / 2

∆<em>x</em> = 20.00 m

5 0
2 years ago
A space probe lands on a newly discovered planet. A small canister is released from the probe and falls a distance of 3 m in 0.5
ivanzaharov [21]

Answer:

24m/s²

Explanation:

Given

Distance S = 3m

Time of fall = 0.5sec

Required

Acceleration due to gravity

Using the equation of motion

S = ut+1/2gt²

Substitute the given values

3 = 0+1/2g(0.5)²

3 = 1/2(0.25)g

3 = 0.125g

g = 3/0.125

g = 24

Hence the value for the acceleration of gravity on this new planet is 24m/s²

3 0
2 years ago
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