Answer:
e) indicated that the speed of light is the same in all inertial reference frames.
Explanation:
In 18th century, many scientists believed that the light just like air and water needs a medium to travel. They called this medium <em>aether</em>. They believed that even the space is not empty and filled with aether.
Michelson and Morley tried to prove the presence and speed of this aether through an interference experiment in 1887. They made an interferometer in which light was emitted at various angles with respect to the supposed aether. Both along the flow and against the flow to see the difference in the speed of light. But they did not find no major difference and thus it became the first proof to disprove the theory of aether.
It thus proved that the speed of light remains same in all inertial frames.
Also, it became a base for the special theory of relativity by Einstein.
D) the mass of the star is the correct answer.
Answer:
The maximum traverse acceleration is 
Explanation:
Generally the maximum transverse acceleration is mathematically represented as
Where 
is the angular velocity which is mathematically evaluated as
Substituting the values given in the question
A is the A is amplitude with a value of 2.0mm 
Substituting this into the formula for maximum transverse acceleration
1) Call F1 the larger force and F1x and F1y its its x-and-y- components.respectively.
I will use the complementary angle: 90 - 25 = 65 to work with the normal convention.
=> cos(65) = F1x / F1 => F1x = - F1*cos(65) (I choose negative as the west direction)
=> sin(65) = F1y / F1 => F1y = F1*sin(65) (I choose positive the north direction)
2) Call F2 the shorter force and F2x and F2y its components
=> cos(x) = F2x / F2 => F2x = F2*cos(x)
=> sin(x) = F2y / F2=> F2y = F2*sin(x)
3) You know that:
- F1 = 2F2
- The net force in the y direction is 430 N
- The net force in the x direction is 0
a) F1x + F2x = 0
=> -F1*cos(65) + F2*sin(x) = 0
=> F1*cos(65) = F2 sin(x) => sin(x) = [F1/F2] cos(65)
Remember F1 = 2F2 => F1/F2 = 2 => sin(x) = 2 cos(65) = 0.84524
=> x = arcsin(0.84524) = 57.7
b) F1y + F2y = 430 =>
F1 sin(65) + F2*sin(57.7) = 430 =>
0.9060F1 + 0.84524F2 430
F1 = 2F2 => 0.9060*2F2 + 0.84524F2 = 430 => 1.7512F2 = 430
=> F2 = 430 / 1.7512 = 245.54 N
=> F1 = 2*245.54 =491.1N
There you have the two forces.
The angle of the shorter force is 57.7 measured from the east to the north (this is north of east), which would be 90 - 57.7 = 32.3 degrees east of north..
Then the shorter force is 245.5 N at 32.3 degrees east of north
And the larger force is 491.1 N at 25.0 degrees west of north.
