Answer:
8.637 m
Explanation:
Using
R = (U²sin2θ)/g.................. Equation 1
Where R = Range, U = initial velocity, θ = angle of projection, g = acceleration due to gravity.
Note: For maximum Range, θ = 45°, then sin2θ = sin90° = 1
Therefore,
Rmax = U²/g..................... Equation 2
Given: U = 9.2 m/s, g = 9.8 m/s²
Substitute into equation 2
Rmax = 9.2²/9.8
Rmax = 84.64/9.8
Rmax = 8.637 m
Hence the maximum range = 8.637 m