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juin [17]
3 years ago
11

show answer No Attempt Treated as a projectile, what is the maximum range, in meters, obtainable by a person if he or she has a

take-off speed of 9.2 m/s? Assume the motion is over level ground and the initial velocity makes an angle of 45° with the horizontal.

Physics
2 answers:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

8.637 m

Explanation:

Using

R = (U²sin2θ)/g.................. Equation 1

Where R = Range, U = initial velocity, θ = angle of projection, g = acceleration due to gravity.

Note: For maximum Range, θ = 45°, then sin2θ = sin90° = 1

Therefore,

Rmax = U²/g..................... Equation 2

Given: U = 9.2 m/s, g = 9.8 m/s²

Substitute into equation 2

Rmax = 9.2²/9.8

Rmax = 84.64/9.8

Rmax = 8.637 m

Hence the maximum range = 8.637 m

Katen [24]3 years ago
3 0

Answer: R=8.64 meters

Explanation:

in the attachment

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3 years ago
what was the temperature change in Celsius degree if it is changed from 44 degree fahrenheit to -56 degree fahrenheit​
wel

Answer:

-11.11 degree Celsius

Explanation:

The change was 44 degree fanhereit

To 56 degree fanhereit

Therefore the temperature range can be calculated as follows

56-44

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3 years ago
What is the weight of an object with a mass of 6.0 kg on Earth?
gregori [183]
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3 0
3 years ago
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When the Glen Canyon hydroelectric power plant in Arizona is running at capacity, 690 m3 of water flows through the dam each sec
bixtya [17]

Answer:

1340.2MW

Explanation:

Hi!

To solve this problem follow the steps below!

1 finds the maximum maximum power, using the hydraulic power equation which is the product of the flow rate by height by the specific weight of fluid

W=αhQ

α=specific weight for water =9.81KN/m^3

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Q=flow=690m^3/s

W=(690)(220)(9.81)=1489158Kw=1489.16MW

2. Taking into account that the generator has a 90% efficiency, Find the real power by multiplying the ideal power by the efficiency of the electric generator

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3 years ago
An object on Earth weighs 150 N. What is its mass?
Alex777 [14]

Answer:

\tt \: mass \:  =  \frac{weight}{acceleration \: due \: to \: gravity}

\longrightarrow \tt \:  \frac{150}{10}

\longrightarrow \boxed{ \tt{15 \: kg}}

  • Our final answer is 15 kg .

----------- HappY LearninG<3 ------------

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2 years ago
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