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juin [17]
3 years ago
11

show answer No Attempt Treated as a projectile, what is the maximum range, in meters, obtainable by a person if he or she has a

take-off speed of 9.2 m/s? Assume the motion is over level ground and the initial velocity makes an angle of 45° with the horizontal.

Physics
2 answers:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

8.637 m

Explanation:

Using

R = (U²sin2θ)/g.................. Equation 1

Where R = Range, U = initial velocity, θ = angle of projection, g = acceleration due to gravity.

Note: For maximum Range, θ = 45°, then sin2θ = sin90° = 1

Therefore,

Rmax = U²/g..................... Equation 2

Given: U = 9.2 m/s, g = 9.8 m/s²

Substitute into equation 2

Rmax = 9.2²/9.8

Rmax = 84.64/9.8

Rmax = 8.637 m

Hence the maximum range = 8.637 m

Katen [24]3 years ago
3 0

Answer: R=8.64 meters

Explanation:

in the attachment

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3 0
2 years ago
Which scientist first suggested that the sun was at the center of the solar system?
pogonyaev

Answer:

Nicolaus Copernicus

Explanation:

With the development of the heliocentric model by Nicolaus Copernicus in the 16th century, the Sun was believed to be the center of the Universe, with the planets (including Earth) and stars orbiting it.

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3 years ago
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lisov135 [29]

The net torque on the seesaw is 294 Nm.

<h3>What is torque?</h3>

Torque is the force that tends to rotate the body to which it was applied.

To calculate the net torque, we use the formula below

Formula:

  • τ = mgd-m'gd'........... Equation 1

Where:

  • τ = Net torque
  • m = Jenny's mass
  • m' = Tom's mass
  • d = Jenny's distance from the pivot
  • d' = Tom's distance from the pivot
  • g = acceleration due to gravity

From the question,

Given:

  • m = 40 kg
  • m' = 30 kg
  • d = 1.5 m
  • d' = 1 m
  • g = 9.8 m/s²

Substitute these values into equation 1

  • τ = (40×1.5×9.8)-(30×1×9.8)
  • τ  = 588-294
  • τ  = 294 Nm

Hence, The net torque on the seesaw is 294 Nm.

Learn more about torque here: brainly.com/question/14839816

5 0
2 years ago
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3 years ago
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During an all-night cram session, a student heats up a 0.607 liter (0.607 x 10- 3 m3) glass (Pyrex) beaker of cold coffee. Initi
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Answer: 0.00000938422m^3

Explanation:

dV=Vø*β*(t1-tø)

The parameters are

dV is the change in volume after temperature increase

Vø =0.607 *10^-3m3 is the initial vokume of coffe at 16.2^0 C

β= coefficient of volume expansion of water at 16.2^0 C is 0.0002/0C

t1= 93.5^0C final temperature

tø=16.2^0 C

Therefore

dV=0.607 *10^-3 *0.0002*(93.5-16.2)

dV= 0.00000938422m^3

This is the volume of coffee that will spill over the container

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