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Tems11 [23]
3 years ago
8

Find the speed of a long distance runner who runs 30km in 6 hours

Physics
2 answers:
slava [35]3 years ago
7 0

30mi/6hrs is a speed of 5 mph, which converts to a pace of 12 min/mi.

Firlakuza [10]3 years ago
3 0

the speed of the long distance runner is 1.38 m/s^2

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If she runs 3,223 meters each day and keeps this up for two weeks, how many miles will she have run
seropon [69]

Answer:

28 miles

Explanation:

3,223 meters/day x 14 days = 45,122 meters

1 meter = 3.28 feet

45,122 meters = 148,000 feet

5280 feet = 1 mile

148,000 feet = 28 miles

5 0
2 years ago
Who came up with the 3 Laws of Motion?
IrinaVladis [17]

Answer:

Isaac Newton came up with the 3 Laws of Motion

6 0
2 years ago
Read 2 more answers
A plane was traveling from Florida to Montreal. It flew for 4 hours and went 1,895 miles. What was its speed?
Contact [7]

Answer:

473.8miles/hr

Explanation:

Given parameters:

Time of flight  = 4hrs

Distance traveled  = 1895miles

Unknown:

Speed of the plane  = ?

Solution:

Speed is the rate of distance covered per unit of time.

It is expressed as:

        Speed  = \frac{distance}{time}  

So;

  Speed  = \frac{1895}{4}   = 473.8miles/hr

6 0
3 years ago
Tests reveal that a normal driver takes about 0.75s before he or she can react to a situation to avoid a collision. It takes abo
netineya [11]

Answer:

<u>NORMAL DRIVER: </u>d = 73.3 ft

<u>DRUNK DRIVER: </u>d = 172.3

Explanation:

<u>NORMAL DRIVER:</u>

Distance covered in initial 0.75s = 0.75s *44 =  33ft

USING THE THIRD EQUATION OF MOTION

V^2-U^2 = 2as

0-(44)^2 = 2 (-24) s

s = 1936/48 =40.3 ft

d = 33 + 40.3 = 73.3 ft

<u>DRUNK DRIVER:</u>

Distance covered in initial 3s = 3s *44 =  132 ft

USING THE THIRD EQUATION OF MOTION

V^2-U^2 = 2as

0-(44)^2 = 2 (-24) s

s = 1936/48 =40.3 ft

d = 132 + 40.3 = 172.3 ft

6 0
3 years ago
What will be the temperature reading in Fahrenheit scale whe eading is 310 k?​
Otrada [13]

The temperature reading in Fahrenheit scale when reading 310 K is  98.6F

<h3>What is temperature?</h3>

Temperature is the degree of hotness or coldness of the object.

Given is a temperature in Kelvin scale = 310 K

Temperature on centigrade scale = 310 -273 = 37°C

Temperature conversion from Centigrade to Fahrenheit is

C/5 = F -32/9

Plug the value, we get

37/5 = F-32/9

66.6 = F -32

F = 32+66.6 =

F = 98.6

Thus, the temperature of 310 K in Fahrenheit is 98.6F.

Learn more about temperature.

brainly.com/question/11464844

#SPJ1

5 0
2 years ago
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