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3 years ago

Find the speed of a long distance runner who runs 30km in 6 hours

Physics

2 answers:

slava [35]3 years ago

7 0

30mi/6hrs is a speed of 5 mph, which converts to a pace of 12 min/mi.

Firlakuza [10]3 years ago

3 0

the speed of the long distance runner is 1.38 m/s^2

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A dog, with a mass of 10.0 kg, is standing on a flatboat so that he is 22.5 m from the shore. He walks 7.8 m on the boat toward

marissa [1.9K]

Answer:16.096

Explanation:

Given

mass of dog $\left ( m_d\right )=10kg$

mass of boat $\left ( m_b\right )=46kg$

distance moved by dog relative to ground= $x_d$

distance moved by boat relative to ground= $x_b$

Distance moved by dog relative to boat=7.8m

There no net force on the system therefore centre of mass of system remains at its position

0= $m_d\times x_d+m_b\dot x_b$

0= $10\times x_d+46\dot x_b$

$x_d=-4.6x_b$

i.e. boat will move opposite to the direction of dog

Now

$|x_d|+|x_b|=7.8$

substituting $x_d$ value

$5.6|x_b|=7.8$

$|x_b|=1.392m$

$|x_d|=6.4032m$

now the dog is 22.5-6.403=16.096m from shore

4 0

3 years ago

What energy transformation occurs when a skydiver first jumps from a plane?

SSSSS [86.1K]

Hi
I think the answer is:
GRAVITATIONAL POTENTIAL ENERGY TRANSFORMS INTO KINETIC ENERGY.
HOPE IT HELPS.

4 0

3 years ago

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A student sees a newspaper ad for an apartment that has 2030 square feet (ft2) of floor space. How many square meters of area ar

Vilka [71]

Square feet or square meters?

8 0

2 years ago

At an air show a jet flies directly toward the stands at a speed of 1200 km/h, emitting a frequency of 3500 Hz, on a day when th

kenny6666 [7]

Answer:

(a): The frequency received by the observers is f'= 138,062.28 Hz.

(b): When the plane flies directly away from them, they receive a frequency of f'= 1772.46 Hz.

Explanation:

Vf= 333.33 m/s

Vo= 0 m/s

V= 342 m/s

f= 3500 Hz

(a) f' = f * ( V / (V - Vf) )

f'= 138062.28 Hz

(b) f'= f* ( V / (V - (- Vf) )

f'= 1772.46 Hz

4 0

3 years ago

An object of mass 0.50 kg is transported to the surface of Planet X where the object’s weight is measured to be 20 N. The radius

Olin [163]

Answer:

$g'=40\ m.s^{-2}$

Explanation:

Given:

mass of the object, $m=0.5\ kg$

weight of the object on planet x, $W=20\ N$

radius of the planet, $R=4\times10^6\ m$

radial distance between the planet and the object, $r=2\times 10^6\ m$

<u>Now free fall acceleration on planet X:</u>

$W=m.g'$

$20=0.5\times g'$

$g'=40\ m.s^{-2}$ irrespective of the height.

8 0

3 years ago

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