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ikadub [295]
3 years ago
15

How do you solve 3-5?

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer: -2

Step-by-step explanation:

You added a subtract sign, so I subtracted. Since it is 3, the numbers go down to the negatives. Ending up a Negative 2 (-2)

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What is y + 10 = -3(x + 10) in slope-intercept form?
Inga [223]

Answer:

y= -3x-40

Step-by-step explanation:

first distribute

y+10= -3x-30

than subtract 10

y= -3x-40

4 0
3 years ago
Help me please &lt;3<br><br> place &lt;,&gt;, or = in the blank <br> 17/2 ________√70
Georgia [21]

Answer:

>

Step-by-step explanation:

17/5 is 8.5 but √70 is 8.3 something that for 17/2>√70

7 0
3 years ago
Questions:
Nimfa-mama [501]
Bread - 3 choices
Meat - 5 choices
Veggies - 7 choices

1br 1mt 1vg = 3×5×7 = 105

1br 2mt 3 vg = 3×5×4×7×6×5 =12600

7vg 1br = 3×1 = 3
6 0
3 years ago
Find the length of the following​ two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 &lt; t &lt; 16
andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)}     dt

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)}     dt

Doing the operations inside of the brackets the derivatives are:

1 ) (\frac{d((1/2)t^2)}{dt} )^2= t^2

2) \frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1

Entering these values of the integral is

r(t)= \int\limits^{16}_{0}  \sqrt{t^2 +2t+1}     dt

It is possible to factorize the quadratic function and the integral can reduced as,

r(t)= \int\limits^{16}_{0} (t+1)  dt= \frac{t^2}{2} + t

Thus, evaluate from 0 to 16

\frac{16^2}{2} + 16

The value is r= 144 units

5 0
3 years ago
Lindy puts £ 78 into an account which pays inrerest at a rate of 5% per anum. What will be the simple interest after 6 years .wh
Alika [10]

Answer:

Interest: £23.4

Amount: £101.4

Step-by-step explanation:

6 × 5/100 × 78 = 23.4

Balance: 78 + 23.4 = 101.4

5 0
3 years ago
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