Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. What is the component of force effecti
ve in pulling the sled horizontally along the ground?
2 answers:
When a force, F, is applied to an object at an angle,θ, to compute for the horizontal and vertical components, we have the following
So, for this particular problem, given that the force applied to the sled is 4.00 N at 62⁰. Thus, the horizontal component of the force is equal to
F = 4.00(cos62⁰) = 1.88 N
Therefore, the horizontal force is 1.88 N.
Answer: 1.88 N
So, for this particular problem, given that the force applied to the sled is 4.00 N at 62⁰. Thus, the horizontal component of the force is equal to
F = 4.00(cos62⁰) = 1.88 N
Therefore, the horizontal force is 1.88 N.
Answer: 1.88 N
You want to draw a free body diagram of the forces on the sled in the horizontal x-direction.
If you visualize the system in an x-y coordinate plane, the force along the x-direction is the angle it makes with the x-axis multiples by the force.
The angle made with the x-axis is cosine of the angle theta.
Please see picture attached.
If you visualize the system in an x-y coordinate plane, the force along the x-direction is the angle it makes with the x-axis multiples by the force.
The angle made with the x-axis is cosine of the angle theta.
Please see picture attached.
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F=
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Answer:
The displacement is 6.71 [m} and the angle is 63.4° to the north of east
Explanation:
Using a sketch showing Dante's displacement, we can find each of the points Dante moves through. First, it moves 4 blocks east, the new coordinate (4.0), then moves 3 blocks south and we will get the new coordinate (4, -3). Then Dante moves 1 block west, thus the new point is (3, -3). And finally it moves 9 blocks north where the new coordinate in and gets -3 - (-9) = + 6.
The displacement can be found using the equation for the straight line.
We can realize that the triangle formed is a right triangle, therefore we can find the angle of the displacement.