Answer:
Explanation:
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In this case, according to the given chemical equation, it turns out possible for us to realize there is a 4:3 mole ratio of chromium(III) nitrate to lead(IV) nitrate, and therefore, we can calculate the moles of the former by applying the shown below stoichiometry setup:
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Answer:
You could write about someone stealing something
Explanation:
And further explain the panic you felt and how the atmosphere changed
Answer:
5.41 x 10²² g
Explanation:
Data Given:
no. of moles of sodium = 2.35 x 10²¹ moles
mass of sodium = ?
Solution:
Formula used
no. of moles = mass in grams / molar mass
To find mass rearrange the above equation:
mass in grams = no. of moles x molar mass. . . . . . (1)
- molar mass of Sodium (Na) = 23 g/mol
Put values in equation 1
mass in grams = 2.35 x 10²¹ moles x 23 g/mol
mass in grams = 5.41 x 10²² g
So,
mass of Sodium (Na) = 5.41 x 10²² g
Answer:
two electrons are lost by magnesium to form magnesium ion (Mn+2) and gained by two oxygen atoms (O-)
6g...........3g..........1,5g........0,75g
0d..........14d.........28d.........42d
After 42 days 0,75g of Phoshorus-32 will remain.
