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SCORPION-xisa [38]
3 years ago
6

Which of the following tools was responsible for advancing our knowledge of cells over the past 400 years?

Chemistry
1 answer:
Radda [10]3 years ago
7 0

Answer:

I have no clue sorry

Explanation:

good luck

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Show the difference between a saturated hydrocarbon and an unsaturated hydrocarbon.
harkovskaia [24]
Saturated hydrocarbons consists of C-C single bond whereas Unsaturated hydrocarbons consists C-C double/triple bond.
4 0
3 years ago
Based on the activity series, which one of the reactions below will occur (Spontaneous)? A. Mn (s) + NiCl2 (aq) → MnCl2 (aq) + N
kap26 [50]

Answer:

Mn (s) + NiCl2 (aq) → MnCl2 (aq) + Ni

Explanation:

The order of displacement of metals from aqueous solution by another metal is defined by the activity series of metals.

The activity series arranges metals in order of reactivity and increasing electrode potentials. The less negative the electrode potential of a metal is, the less reactive it is and the lower it is found in the activity series.

Nickel has a less negative electrode potential than manganese hence it is displaced from an aqueous solution of its salt by manganese spontaneously.

8 0
3 years ago
You have 2.7 moles of carbon. How many atoms do you have?
Gelneren [198K]

Answer:

1.63 × 10²⁴ atoms.

Explanation:

To calculate the number of atoms (N) contained in 2.7moles of carbon, we multiply the number of moles (n) by Avogadro's number (6.02 × 10²³).

That is, N = n × nA

Where;

N = number of atoms

n = number of moles (mol)

nA = Avogadro's numbe

N = 2.7 × 6.02 × 10²³

N = 16.254 × 10²³

N = 1.63 × 10²⁴ atoms.

Hence, there are 1.63 × 10²⁴ atoms in 2.7moles of Carbon.

4 0
3 years ago
Finding number of atoms 9H2SO4
Molodets [167]

Explanation:

23 are the number of atoms

7 0
3 years ago
What volume of lead (of density 11.3 g/cm3) has the same mass as 330 cm3 of a piece of redwood (of density 0.38 g/cm3)?
zimovet [89]

Answer:

The sample of lead has a volume of 11.1 cm³

Explanation:

<u>Step 1:</u> Data given

x cm³ lead has a density of 11.3 g/cm³

it has the same mass as 330cm³ of a piece of redwood with density 0.38g/cm³

<u>Step 2</u>: Calculate mass of the piece of redwood

Density = mass/volume

mass = density * volume

Mass of the piece of redwood = 0.38 g/cm³ * 330cm³ = 125.4 grams

Since the sample of lead has the same mass, it also has a mass of 125.4 grams

<u>Step 3</u>: Calculate volume of the lead

Density = mass/ volume

Volume = mass/ density

Volume of lead = 125.4g / 11.3g/cm³ = 11.097 cm³≈11.1 cm³

The sample of lead has a volume of 11.1 cm³

3 0
3 years ago
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