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Karolina [17]
3 years ago
12

A 3-m-high, 11-m-wide rectangular gate is hinged at the top edge at A and is restrained by a fixed ridge at B. Determine the hyd

rostatic force exerted on the gate by the 5-m-high water and the location of the pressure center. Take the density of water to be 1000 kg/m3 throughout. The hydrostatic force exerted on the gate by the water is kN. The vertical distance of the pressure center from the free surface of water is m..
Engineering
1 answer:
serg [7]3 years ago
5 0

Answer:

its a

Explanation:

its a

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In a particular application involving airflow over a heated surface, the boundary layer temperature distribution may be approxim
diamong [38]

Answer:

Explanation:

In a particular application involving airflow over a heated surface, the boundary layer temperature distribution, T(y), may be approximated as:

[ T(y) - Ts / T∞ - Ts ] = 1 - e^( -Pr (U∞y / v) )

where y is the distance normal to the surface and the Prandtl number, Pr = Cpu/k = 0.7, is a dimensionless fluid property. a.) If T∞ = 380 K, Ts = 320 K, and U∞/v = 3600 m-1, what is the surface heat flux? Is this into or out of the wall? (~-5000 W/m2 , ?). b.) Plot the temperature distribution for y = 0 to y = 0.002 m. Set the axes ranges from 380 to 320 for temperature and from 0 to 0.002 m for y. Be sure to evaluate properties at the film temperature.

3 0
3 years ago
Early American rockets used an RC circuit to set the time for the rocket to begin re-entry after launch (true story). Assume the
koban [17]

Answer:

C = 0.3 F

Explanation:

The expression for a voltage in a capacitor with an initial voltage V₀, as a function of time, is given by the following equation:

V= Vo*e^{-t/RC}

When V = =.37*V₀, we have the following expression:

\frac{V}{Vo} = e^{-t/RC} = 0.37

Applying ln to both sides, we have:

\frac{-t}{RC} = ln 0.37 = -1

⇒ t = R*C

if t= 300 s, and R = 10³ Ω, we can solve for C as follows:

C = \frac{t}{R} = \frac{3e2 s}{1e3 ohms} = 0.3 F

So, the required value for C is 0.3 F.

3 0
3 years ago
A fluid flows steadily through a pipe with a uniform cross sectional area. The density of the fluid decreases to half its initia
Vikentia [17]

Answer:

c. V2 equals V1

Explanation:

We can answer this question by using the continuity equation, which states that:

A_1 v_1 = A_2 v_2 (1)

where

A1 is the cross-sectional area in the first section of the pipe

A2 is the cross-sectional area in the second section of the pipe

v1 is the velocity of the fluid in the first section of the pipe

v2 is the velocity of the fluid in the second section of the pipe

In this problem, we are told that the pipe has a uniform cross sectional area, so:

A1 = A2

As a consequence, according to eq.(1), this means that

v1 = v2

so, the velocity of the fluid in the pipe does not change.

5 0
3 years ago
What is the ILS stand for
Alika [10]

Answer:

Instrument Landing System

Explanation:

The ILS works by sending radio waves from the runway to the aircraft. Which is then intercepted and is used to guide the aircraft onto the runway.

6 0
3 years ago
Read 2 more answers
What is voltage drop?
lord [1]

Answer:

Explanation:

It is the voltage a voltmeter would read when connected across something that has resistance.

___________0_________O______O_______

|                                                                               |

|                                              |                                |

|_____________________|  |_____________ |

                                              |

The diagram above is supposed to represent 3 lightbulbs connected in series. The vertical lines in the middle are supposed to be a battery which powers the three light bulbs. If you put a voltmeter across one of the lightbulbs, it will read a voltage that is 1/3 of the voltage of the battery.

Answer

That reading you get across the one light bulb is The Voltage Drop.

                                             

6 0
2 years ago
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