Answer:
![N_3=\dfrac{T_1}{T_3}N_1](https://tex.z-dn.net/?f=N_3%3D%5Cdfrac%7BT_1%7D%7BT_3%7DN_1)
Explanation:
In the diagram there three gears in which gear 1 is input gear ,gear 2 is idle gear and gear 3 is out put gear.
Lets take
![Speed\ of\ gear 1=N_1](https://tex.z-dn.net/?f=Speed%5C%20of%5C%20gear%201%3DN_1)
![Number\ of\ teeth\ of\ gear 1=T_1](https://tex.z-dn.net/?f=Number%5C%20of%5C%20teeth%5C%20of%5C%20gear%201%3DT_1)
![Speed\ of\ gear 3=N_3](https://tex.z-dn.net/?f=Speed%5C%20of%5C%20gear%203%3DN_3)
![Number\ of\ teeth\ of\ gear 3=T_3](https://tex.z-dn.net/?f=Number%5C%20of%5C%20teeth%5C%20of%5C%20gear%203%3DT_3)
All external matting gears will rotates in opposite direction with respect to each other.
So the speed of gear third can be given as follows
![\dfrac{T_1}{T_3}=\dfrac{N_3}{N_1}](https://tex.z-dn.net/?f=%5Cdfrac%7BT_1%7D%7BT_3%7D%3D%5Cdfrac%7BN_3%7D%7BN_1%7D)
![N_3=\dfrac{T_1}{T_3}N_1](https://tex.z-dn.net/?f=N_3%3D%5Cdfrac%7BT_1%7D%7BT_3%7DN_1)
Answer:
Determine the added thrust required during water scooping, as a function of aircraft speed, for a reasonable range of speeds.= 132.26∪
Explanation:
check attached files for explanation
Answer:
// Program is written in C++
// Comments are used to explain some lines
// Only the required function is written. The main method is excluded.
#include<bits/stdc++.h>
#include<iostream>
using namespace std;
int divSum(int num)
{
// The next line declares the final result of summation of divisors. The variable declared is also
//initialised to 0
int result = 0;
// find all numbers which divide 'num'
for (int i=2; i<=(num/2); i++)
{
// if 'i' is divisor of 'num'
if (num%i==0)
{
if (i==(num/i))
result += i; //add divisor to result
else
result += (i + num/i); //add divisor to result
}
}
cout<<result+1;
}
Answer:
Explanation:
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