Answer:
A) oxidizing agent is SO2
B) NaClO is the oxidizing agent
Explanation:
A) This is a redox reaction in which oxidation and reduction occur simultaneously.
Thus, in 2H2S(g) + SO2(g) -> 2H2O(l) + 3S(s);
H2S is reduced as follows;
H2S → S + 2H+ + 2e−
We can see that SO2 has been reduced while H2S gets oxidized since it has changed state from - 2 to 0 . Thus sulphur dioxide is the oxidizing agent.
B) SO2(g) + H2O(l) + NaClO(aq) -> NaCl(aq) + H2SO4(aq)
In this, SO2 undergoes oxidation and NaClO is the oxidizing agent
Because it happens somewhere
An example of an allotrope is carbon:
Carbon can exist in graphite, diamond and amorphous
Reaction
SiCl₄+ 2Mg ⇒ Si + 2MgCl₂
to find limiting reagents: divide the number of moles by their coefficients
SiCl₄ = 1 mole : 1 (coefficient) = 1
Mg = 5 mole : 2 (coefficient) = 2.5
SiCl₄ as a limiting reactant (smaller), and Mg as an excess
then all the compounds involved in the reaction are based on moles of SiCl₄
Si produced =

Reacted Mg (excess) = 2/1 x 1 = 2 mole
mole Mg remaining = 5 - 2 = 3 mole