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adoni [48]
3 years ago
15

Find the velocity of a swimmer who swims exactly 220 m toward the shore in 72 s.

Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer: 3.06m/s

Explanation:

Distance covered by swimmer = 220 m

Time taken by swimmer = 72 s.

Velocity = ?

Recall that velocity is the rate of change of distance per unit time. it is measured in metres per second.

Velocity = Distance / time taken

Velocity = 220m / 72seconds

Velocity = 3.055 m/s (approximate to 3.06m/s)

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The molecules of solid CO2 are much closer together than the molecules of CO2 gas.

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3 years ago
Which organelle in cytoplasm is responsible for carrying hereditary information? ​
Amanda [17]

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Nucleus

Explanation:

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3 0
3 years ago
A sample of 10.5 g of nitrogen reacts with 20.2 g of hydrogen to produce ammonia. (36 points
BartSMP [9]

Answer:

Explanation:

A. 55

B. 43

C. 14

D. 29

6 0
2 years ago
How many moles of pcl5 can be produced from 28.0 g of p4 (and excess cl2)?
BARSIC [14]
P₄ + 10Cl₂ ---> 4PCl₅
stoichiometry of P₄ to PCl₅ is 1:4
number of moles of P₄ reacted - 28.0 g / 124 g/mol = 0.22 mol 
Cl₂ is in excess therefore P₄ is the limiting reactant, amount of product formed depends on amount of limiting reactant present 
according to molar ratio of 1:4
number of PCl₅ moles formed  -0.22 mol x 4 = 0.88 mol 
0.88 mol of PCl₅ is formed 

5 0
3 years ago
Write the condensed formula from left to right, starting with (CH3)x where x is a number.
pochemuha

Complete question:

Write the condensed formula from left to right, starting with (CH3)x where x is a number.

See attached image for the structure formula of the compound

Answer:

(CH₃)₂CHC(CH₃)₃ named as 2,2,3-Trimethylbutane

Explanation:

If we number the longest chain of the carbon starting from the left, we will observe that there are four carbons in the straight chain as shown in the image.

Starting from first carbon from the left of the carbon chain, at carbon number number 2, there two alkyl group, that is two methyl (CH3 is two). Also at carbon number 3, there are three alkyl group, that is three methyl (CH3 is three).

The condensed formula will be written as;

(CH₃)₂CHC(CH₃)₃

This compound is named as 2,2,3-Trimethylbutane, an isomer of Heptane

3 0
3 years ago
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