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jekas [21]
3 years ago
5

One reason ionic compounds do not dissolve well in nonpolar solvents is that ___.

Chemistry
1 answer:
Lapatulllka [165]3 years ago
6 0

Answer:

d. there are no forces of attraction between ions and nonpolar molecules.

Explanation:

Solubility is determined by the principle , "like dissolves like" .

i.e. , if a compound is polar then it will dissolve in a polar compound only , and

if a compound is non - polar then it will dissolve in a non - polar compound only .

Ionic compound , are polar in nature , i.e. , have a positive and negative charge , polar solution can only dissolve in polar ,

As ,  there will be interaction between the opposite charge , and hence will dissolve .

And , in case of a polar and non polar solution , there won't be any interaction , and hence will not dissolve .

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What is the rate law for the uncatalyzed reaction?
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What is the rate law for the uncatalyzed reaction?

Metals often form several cations with different charges. Cerium, for example, forms and ions, and thallium forms and ions. Cerium and thallium ions react as follows:  

2Ce^4+(aq) + Tl^+(aq) ---> 2Ce^3+(aq)+Tl^3+(aq)  

This reaction is very slow and is thought to occur in a single elementary step. The reaction is catalyzed by the addition of Mn^2+ according to the following mechanism:  

Ce^4+(aq)+Mn^2+(aq) ---> Ce^3+(aq)+Mn^3+(aq)  

Ce^4+(aq)+Mn^3+(aq) ---> Ce^3+ (aq) + Mn^4+ (aq)  

Mn^4+(aq) + Tl^+(aq) ---> Mn^2+(aq) + Tl^3+(aq)  

If the uncatalyzed reaction occurs in a single elementary step, why is it a slow reaction?  

1)The probability of an effective three-particle collision is low.  

2) The transition state is low in energy.  

3) The reaction requires the collision of three particles with the correct energy and orientation.  

4) All reactions that occur in one step are slow.  

The catalyzed reaction is first order in [Ce^4+] and first order in [Mn^2+]. Which of the steps in the catalyzed mechanism is rate determining?  

Based on their available oxidation states, rank the following metals on their ability to catalyze this and other oxidation-reduction reactions.  

Rank from best to worst catalyst.  

Vanadium, titanium, manganese

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2 years ago
Calculate the theoretical value for the number of moles of CO2 that should have been produced in each balloon assuming that 1.45
musickatia [10]

Answer:

For 1 antacid tablet (in ballon1) we get .0173 moles of CO2

for 2 tablets (in balloon 2) we get: 2*0,0173=  0.0346 moles of CO2

For 3 tablets (in balloon 3) we get 3* 0.0173 = 0.0519 moles of CO2

Explanation:

The complete question:

Calculate the theoretical value for the number of moles of CO2 that should have been produced in each balloon assuming that 1.45 g of NaHCO3 is present in an antacid tablet. Use stoichiometry (a mole ratio conversion must be present) to find your answers (there should be three: one answer for each balloon).

Balloon 1 had 1 antacid tab

Baloon 2 had 2

Balloon 3 had 3

Step 1: Data given

1.45 g of NaHCO3 is present in an antacid tablet

Molar mass of NaHCO3 = 84.00 g/mol

Step 2: The balanced equation

NaHCO3 + H2O → NaOH + H2O + CO2

Step 3: Calculate moles of NaHCO3

Moles NaHCO3 = mass NaHCO3 / molar mass NaHCO3

1.45g / 84.0 g/mol = .0173 moles

Step 4: Calculate moles CO2

For 1 mol NaHCO3 we need 1 mol H2O to produce 1 mol NaOH 1 mol H2O and 1 mol CO2

For 0.0173 moles NaHCO3 we'll get 0.0173 moles CO2

so for 1 antacid tablet we get .0173 moles of CO2

for 2 tablets we get: 2*0,0173 =  0.0346 moles of CO2

For 3 tablets we get 3* 0.0173 = 0.0519 moles of CO2

 

5 0
3 years ago
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