1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
eduard
3 years ago
11

A piano of mass 852 kg is lifted to a height of 3.5 m. How much gravitational potential energy is added to the piano? Accelerati

on due to gravity is g = 9.8 m/s2.
Physics
1 answer:
Sedaia [141]3 years ago
4 0
Gravitational Potential Energy = Mass*Gravity*Height.

GPE = 852 * 9.8 * 3.2
GPE = 26718.72 Newtons. 
You might be interested in
How is energy transferred between two objects at different temperatures?
mojhsa [17]

When calculated energy transferred between objects use the definition of heat as

4 0
3 years ago
anonymous 4 years ago The turbidity levels of water in four locations are shown in the table below. Which of these conclusions i
Tresset [83]
Hello!

The Correct Answer would 100% be:

Option "C".

"People in location C would complain about foul taste in water".

I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)

(Mark As Brainliest IF Helped!)

-TheOneAboveAll :D
4 0
3 years ago
Read 2 more answers
Please help me on this 1 assignment im giving 25 points GOOD LUCK!
kati45 [8]

Answer:

Explanation:

im sorry if this doesn't help but i think  its A

3 0
3 years ago
Which transformation of energy takes place when a slingshot launches a stone? (PE stands for potential energy.) A. elastic PE to
boyakko [2]

B. Elastic potential to kinetic energy

The elastic potential energy in the slingshot will be transferred to the stone as kinetic energy as the stone is launched.

6 0
3 years ago
Read 2 more answers
A dragster starts from rest and travels 1/4 mi in 6.80 s with constant acceleration. What is its velocity when it crosses the fi
Ahat [919]
<h2>Its velocity when it crosses the finish line is 117.65 m/s</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = ?

        Time, t = 6.8 s    

        Displacement, s = 1/4 mi =    400 meters

     Substituting

                      s = ut + 0.5 at²

                      400 = 0 x 6.8 + 0.5 x a x 6.8²

                      a = 17.30 m/s²

Now we have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = ?

     Time, t = 6.8 s

      Acceleration, a = 17.30 m/s²

     Substituting

                      v = u + at  

                      v = 0 + 17.30 x 6.8

                      v = 117.65 m/s

Its velocity when it crosses the finish line is 117.65 m/s

6 0
3 years ago
Other questions:
  • What is the final electron receptor in the light reaction of photosynthesis?
    6·1 answer
  • A beam of EMW in air strikes a sheet of a glass at 75 degrees with the normal in air. You observe that red light makes an angle
    13·1 answer
  • An unbalanced force of 15 N is applied to a 13 kg mass. What is the acceleration of the mass?
    7·1 answer
  • A car is accelerating when it is:________.
    12·1 answer
  • Which device provides electrical energy to run an electric circuit
    14·2 answers
  • Explain why a valve would last longer in the pulmonary position than in the aortic position
    12·1 answer
  • A ball is thrown up with a speed of 15m/s. How high will it go before it begins to fall? ( g = 10m/s2 )
    7·1 answer
  • 3V battery is used with a 15 ohm resistance.What is the current?
    9·1 answer
  • A 12,500 kg railroad freight car travels on a level track at a speed of 5.2 m/s. It collides and couples with a 22,600 kg second
    8·1 answer
  • Projectile effects are a hazard in __________________. magnetic resonance imaging (MRI) fields pediatric units emesis stations o
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!