Answer is: 3. Water and carbon dioxide should both be moved to the products side, and glucose and oxygen should be moved to the reactants side.
Balanced chemical reaction for cellular respiration (convert biochemical energy):
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy, or:
glucose + oxygen → carbon dioxide + water + energy.
This reaction is exothermic (energy is released).
Answer:
The answers are in the explanation.
Explanation:
The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:
Increasing temperature of ice from -10°C - 0°C:
Q = S*ΔT*m
Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g
Q = 2.06J/g°C*10°C*10g
Q = 206J
Change from solid to liquid:
The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:
Q = 333.55J/g*10g
Q = 3335.5J
Increasing temperature of liquid water from 0°C - 100°C:
Q = S*ΔT*m
Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g
Q = 4.18J/g°C*100°C*10g
Q = 4180J
Change from liquid to gas:
The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:
Q = 2260J/g*10g
Q = 22600J
Increasing temperature of gas water from 100°C - 120°C:
Q = S*ΔT*m
Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g
Q = 1.87J/g°C*20°C*10g
Q = 374J
Total Energy:
206J + 3335.5 J + 4180J + 22600J + 374J =
30695.5J =
30.7kJ
Answer:
Your answer has to be B. Camouflage
Explanation:
An atom of vanadium
(V) has 23 electrons.
Given :
A vanadium (V) atom with 23 protons and has a net charge of 0.
To find:
The number of electrons in a vanadium atom
Solution:
Number of protons in vanadium atom = 23
The 0 net charge on the atom indicates that the atom has an equal number of protons and electrons which makes it a neutral atom.
Number of electrons in vanadium atom = Number of protons in vanadium atom = 23
An atom of vanadium
(V) has 23 electrons.
Learn more about subatomic particles here:
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