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rusak2 [61]
3 years ago
11

Inquiry Extension Consider a reaction that occurs between solid potassium and chlorine gas. If you start with an initial mass of

15.20 g K, and an initial mass of 2.830 g Cl2, calculate which reactant is limiting. Explain how to determine how much more of the limiting reactant would be needed to completely consume the excess reactant. Verify your explanation with an example
Chemistry
1 answer:
djyliett [7]3 years ago
5 0

Answer:

5 this is the answer call me brainy please

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Which statements describe the elements? Which ones are true and which ones are false?
Alchen [17]

Answer:

Explanation:

Uma declaração verdade é identificada pelo de ela afirmar a verdade diferente das outras opções

8 0
3 years ago
How many molecules of Iron(II)oxide are present in 35.2*10^-23 g of Iron (II)oxide?
slava [35]

Answer:

R.F.M of Iron (II) oxide :

{ \tt{ = (56 \times 2) + (16 \times 3)}} \\  = 160 \: g

Moles :

{ \tt{ \frac{35.2 \times  {10}^{ - 23} }{160} }} \\  = 2.2 \times  {10}^{ - 24}  \: moles

Molecules :

{ \tt{ = 2.2 \times  {10}^{ - 24}  \times 6.02 \times  {10}^{23} }} \\  = 1.3244 \: molecules

4 0
3 years ago
The gas in the piston is at constant temperature. A student increases the pressure on the piston from 2 atm to 3 atm. The observ
azamat
Answer : Option B) Row 1, Volume decreases when pressure increases.

Explanation : According to the boyle's law, when the pressure  of the gas molecules are increased from  2 atm to  3 atm creates a decrease in volume of the gas which then increases the rate of collision of the molecules and makes it more compact than it was before.
5 0
3 years ago
Read 2 more answers
A slice of Swiss cheese contains 41 mg of sodium.
larisa86 [58]

Answer:

a. 41 mg equals 0.041 grams.

b. 41 mg equals 0.0014462 ounces

c. 41 mg equals 9.039*10⁻⁵ pounds

Explanation:

You know that a slice of Swiss cheese contains 41 mg of sodium.

a. What is this mass in grams?

Knowing that 1 mg = 10⁻³ g, you can apply the following rule of three: if 1 mg equals 10⁻³ g or 0.001 grams, 41 mg will be equivalent to how much mass in g?

mass=\frac{41 mg*0.001 g}{1 mg}

mass= 0.041 grams

<u><em> 41 mg equals 0.041 grams.</em></u>

b. What is this mass in ounces?

Knowing that 1 mg = 3.5274 * 10⁻⁵ ounces, you can apply the following rule of three: if 1 mg equals 3.5274 * 10⁻⁵ ounces, 41 mg will be equivalent to how much mass in ounces?

mass=\frac{41 mg*3.5274*10^{-5}ounces }{1 mg}

mass= 1.4462*10 ⁻³ ounces= 0.0014462 ounces

<u><em>41 mg equals 0.0014462 ounces</em></u>

c. What is this mass in pounds?

Knowing that 1 mg = 2.20462 * 10⁻⁶ pounds, you can apply the following rule of three: if 1 mg equals 2.20462 * 10⁻⁶ pounds, 41 mg will be equivalent to how much mass in pounds?

mass=\frac{41 mg*2.20462*10^{-6}pounds }{1 mg}

mass= 9.039*10⁻⁵ pounds

<u><em>41 mg equals 9.039*10⁻⁵ pounds</em></u>

5 0
3 years ago
The ozone "hole" over Antarctica formed as the result of a series of chemical reactions. The loss occurs in part through three c
mixer [17]

Answer:

A)

Cl + O3 --> ClO + O2

2ClO --> ClOOCl

ClOOCl --> 2 Cl + O2

B)

Cl2 + 4O3 -> 2 ClO + 5O2

Explanation:

Step 1: Chlorine atoms react with ozone (O3) to form chlorine monoxide and molecular oxygen

Cl + O3 --> ClO + O2

Step 2: Chlorine monoxide molecules combine to form ClOOCl gas

2ClO --> ClOOCl

Step 3: ClOOCl absorbs sunlight and breaks into chlorine atoms and molecular oxygen

ClOOCl --> 2 Cl + O2

B) Overall Balanced equation

Cl2 + 4O3 -> 2 ClO + 5O2

7 0
3 years ago
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