Answer:
X: Always attractive
Y: Infinite range
Z: Attractive or repulsive
ANSWER IS C
Answer:
40sec
Explanation:
Data
Work = 440 J
Power= 11watt
time = ?
Power = work done/time
===> time = work done/power
= 440/11
= 40sec
Answer:
Velocity = 0.5 m/s South (A)
Explanation:
You need to determine the average rate of velocity.
The equation you will use is velocity = displacement/time
The displacement is 30m South.
The time is 60 seconds.
Plug into the equation Velocity = 30m South/60 s
Velocity = 0.5 m/s South
Answer:
A. 0.0096 W/m²
B. 11.603 dB
C. 827.37 m/s
Explanation:
Parameters given:
Frequency, f = 274Hz
Pressure, P = 101.3 kPa
Temperature, T = 25°C = 298K
Power = 30 mW
Radial distance, = 500 mm = 0.5 m
A. Intensity = Power/Area
Intensity = Power/(4*pi*r²)
= (30 * 10^(-3))/(4 * 3.142 * 0.5²)
= 0.0096 W/m²
B. Pressure(rms) = √(I*ρ*c)
I = Intensity
ρ = density
c = speed of sound
ρ = P/RT
R = gas constant
=> ρ = (101.3 * 10^3) / (298 * 8.314)
ρ = 40.89 kg/m³
=> Pressure(rms) = √(0.0096 * 40.89 * 343)
= √(134.64)
= 11.603 dB = 11.603 * 10^(-6) Pa
C. Acoustic Particle velocity = Intensity/ Acoustic Pressure
Acoustic Particle velocity = 0.0096 / (11.603 * 10^(-6)
Acoustic Particle velocity = 827.37 m/s
