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S_A_V [24]
3 years ago
12

Which number sentences show ways to solve the problem?

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
7 0
One answer could be D
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Need help with number 3 inequalities with variables on both sides
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x ≤ 2

Step-by-step explanation:

We are given the inequality:

\displaystyle{2x-3 \leq \dfrac{x}{2}}

First, get rid of the denominator by multiplying both sides by 2:

\displaystyle{2x\cdot 2-3\cdot 2 \leq \dfrac{x}{2}\cdot 2}\\\\\displaystyle{4x-6 \leq x}

Add both sides by 6 then subtract both sides by x:

\displaystyle{4x-6+6 \leq x+6}\\\\\displaystyle{4x \leq x+6}\\\\\displaystyle{4x-x \leq x+6-x}\\\\\displaystyle{4x-x \leq 6}\\\\\displaystyle{3x \leq 6}

Then divide both sides by 3:

\displaystyle{\dfrac{3x}{3} \leq \dfrac{6}{3}}\\\\\displaystyle{x \leq 2}

Therefore, the answer is x ≤ 2

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I am a cube that has a length, width, and height of 1 unit
OlgaM077 [116]
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Please help me.
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The answer would be theorem Side angle side (aka SAS)
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