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Vikentia [17]
3 years ago
14

Q2. Zara travelled in a train moving at an average speed of 120km/h and covered a distance of 40km towards East. Calculate the t

ime taken by the train to cover this distance.
Physics
1 answer:
san4es73 [151]3 years ago
8 0

Answer: 20 minutes

Explanation:

Given the following :

Average speed of train = 120km/hr

Distance = 40km.

The time take by the train moving at an average speed of 120km/hr to cover a distance of 40km due is ;

Recall:

Speed = distance / time

Therefore,

Time taken = distance covered / speed

Time taken = 40km / 120km/hr

Time taken = 1/ 3 hr

Therefore, 1/3 rd of an hour equals

1/3 × 60 = 20 minutes.

Time taken) 20 minutes

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A point charge of -4.28 pC is fixed on the y-axis, 2.79 mm from the origin. What is the electric field produced by this charge a
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Answer:

E = (-3.61^i+1.02^j) N/C

magnitude E = 3.75N/C

Explanation:

In order to calculate the electric field at the point P, you use the following formula, which takes into account the components of the electric field vector:

\vec{E}=-k\frac{q}{r^2}cos\theta\ \hat{i}+k\frac{q}{r^2}sin\theta\ \hat{j}\\\\\vec{E}=k\frac{q^2}{r}[-cos\theta\ \hat{i}+sin\theta\ \hat{j}]              (1)

Where the minus sign means that the electric field point to the charge.

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

q = -4.28 pC = -4.28*10^-12C

r: distance to the charge from the point P

The point P is at the point (0,9.83mm)

θ: angle between the electric field vector and the x-axis

The angle is calculated as follow:

\theta=tan^{-1}(\frac{2.79mm}{9.83mm})=74.15\°

The distance r is:

r=\sqrt{(2.79mm)^2+(9.83mm)^2}=10.21mm=10.21*10^{-3}m

You replace the values of all parameters in the equation (1):

\vec{E}=(8.98*10^9Nm^2/C^2)\frac{4.28*10^{-12}C}{(10.21*10^{-3}m)}[-cos(15.84\°)\hat{i}+sin(15.84\°)\hat{j}]\\\\\vec{E}=(-3.61\hat{i}+1.02\hat{j})\frac{N}{C}\\\\|\vec{E}|=\sqrt{(3.61)^2+(1.02)^2}\frac{N}{C}=3.75\frac{N}{C}

The electric field is E = (-3.61^i+1.02^j) N/C with a a magnitude of 3.75N/C

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3 years ago
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Match the variables to its definition​
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Answer:

See connections below

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