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Artist 52 [7]
3 years ago
6

When will a seed begin to germinate?

Chemistry
2 answers:
ladessa [460]3 years ago
7 0
1 & 2
Are the correct answer


Hope it helps :)
Vlada [557]3 years ago
4 0
When it has sunlight and water
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Thermal energy always moves from a greater energy level to a lesser energy level
Nookie1986 [14]

Answer:

\fbox{Law -Based \: on \: laws \: of \: thermodynamic}

Explanation:

At constant pressure Thermal energy always moves from a greater energy level to a lesser energy level, laws of thermodynamics prove that.

Nature always likes to attain equilibrium either it's movement of heat energy or flow of water from higher region to lower region. The first and second law of thermodynamics are profe of that, the first law says that the total energy of universe is Constant. Energy can not be destroyed it always changes from one form to another, by work and heat. The second law explains why thermal energy moves from a greater energy level to a lesser energy level, it deals with the change in entropy of a system and surrounding and states heat flows from hot environment to cold environment.

<em><u>Thanks for joining brainly community!</u></em>

6 0
3 years ago
To perform a certain type of blood analysis, lab technicians must perform two procedures. The first procedure requires either on
kirza4 [7]

Answer: There are 6 different outcomes.

Explanation:

There are two options for procedure one (one or two steps) and three options for procedure two (one, two or three steps). If we multiply those options , the result is the total number of outcomes for the analysis.

2 x 3 = 6

These being

- One step on procedure one and one step on procedure two

- One step on procedure one and two steps on procedure two

- One step on procedure one and three steps on procedure two

- Two steps on procedure one and one step on procedure two

- Two steps on procedure one and two steps on procedure two

- Two steps on procedure one and two steps on procedure two

7 0
3 years ago
The enthalpy of reaction changes somewhat with temperature. Suppose we wish to calculate ΔH for a reaction at a temperature T th
Contact [7]

Answer:

-99.8 kJ

Explanation:

We are given the methodology to answer this question, which is basically  Kirchhoff law . We just need to find the heats of formation for the reactants and products and perform the calculations.

The standard heat of reaction is

ΔrHº = ∑ ν x ΔfHº products - ∑ ν x ΔfHº reactants

where ν are the stoichiometric coefficients in the balanced equation, and ΔfHº are the heats of formation at their  standard states.

  Compound                 ΔfHº (kJmol⁻¹)

        SO₂                             -296.8

         O₂                                    0

         SO₃                            -395.8

The balanced chemical equation is

SO₂(g) + ½O₂(g) → SO₃(g)

Thus

Δr, 298K Hº( kJmol⁻¹ ) =  1 x (-395.8) - 1 x (-296.8) = -99.0 kJmol⁻¹

Now the heat capacity of reaction  will be be given in a similar fashion:

Cp rxn = ∑ ν x Cp of products - ∑ ν x Cp of reactants

where ν is as above the stoichiometric coefficient in the balanced chemical equation.

Cprxn ( JK⁻¹mol⁻¹) = 50.7 - ( 39.9 + 1/2 x 29.4 ) = - 3.90

                         = -3.90 JK⁻¹mol⁻¹

Finally Δr,500 K Hº = Δr, 298K Hº +  CprxnΔT

Δr,500 K Hº = - 99 x 10³ J + (-3.90) JK⁻¹ ( 500 - 298 ) K = -99,787.8

                     = -99,787.8 J x 1 kJ/1000 J  = -99.8 kJ

Notice thie difference is relatively small that is why in some problems it is o.k to assume the change in enthalpy is constant over a temperature range, especially if it is a small range of temperatures.

3 0
3 years ago
1.05kg of aluminum what is the heat capacity ?
vitfil [10]
The aluminum can with stand <span>0.942 J° C  of heat </span>
8 0
3 years ago
At 517 mm Hg and 24 °C, a sample of gas occuples a volume of 95 ml. The gas is transferred to a 225-ml flask and the temperature
vodomira [7]

Answer:

P_2=194.78mmHg

Explanation:

Hello,

In this case, we employ the combined ideal gas law in order to understand the volume-gas-pressure behavior as shown below:

\frac{P_1V_1}{T_1}= \frac{P_2V_2}{T_2}

Hence, solving for the final pressure P2, we obtain (do not forget temperature must be absolute):

P_2=\frac{P_1V_1T_2}{V_2T_1}=\frac{517mmHg*95mL*(-8.0+273.15)K}{(24+273.15)K*225mL}\\ \\P_2=194.78mmHg

Best regards.

7 0
4 years ago
Read 2 more answers
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