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vitfil [10]
4 years ago
5

A circular flat coil that has N turns, encloses an area A, and carries a current i has its central axis parallel to a uniform ma

gnetic field B in which it is immersed.
The net torque on the coil is ____.


a) iBA

b) NiA

c) NiB

d) NiAB

e) Zero
Physics
1 answer:
bogdanovich [222]4 years ago
5 0

Answer:

Torque on the coil will be ZERO

Explanation:

As we know that the magnetic moment of the closed current carrying coil is always along its axis and it is given as

M = N i A

now we know that magnetic field is also along the axis of the coil so here as we know the equation of torque given as

\tau = \vec M \times \vec B

so we have

\tau = M B sin0

\tau = 0

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A rocket moves upward, starting from rest with an acceleration of 29.4 m/s^2 for 3.98 s. it runs out of fuel at the end of 3.98
ValentinkaMS [17]
The distance d₁ it rises from rest while the engine is burning is given by
d₁ = d₀ + v₀t + (1/2)at²
d₁ = 0 + 0 + (1/2)·(29.4 m/s²)·(3.98 s)² = 232.85 m
So it gets to 232.85 m and then runs out of fuel.  Its velocity v₁ at this point is given by
v₁ = v₀ + at = (29.4 m/s²)·(3.98 s) = 117 m/s
At this point, gravity begins to slow it down until it reaches its peak where its velocity v₂ is zero.
v₂² = v₁² + 2ad₂
where d₂ is the distance it rises until v=0
Since gravity is decelerating the rocket, a = -g, and we have
0² = (117 m/s)² + 2(-9.8 m/s²)d₂
0 = (117)² - (19.6)·d₂
0 = 13,689 - (19.6)·d₂
d₂ = 13,689/19.6 = 698.42 m
So the total height it rises is given by
d₁ + d₂ = 232.85 m + 698.42 m
= 931.27 m





5 0
4 years ago
The maximum torque on a set of 20 square loops with edge lengths of 6 cm in a 4.0 T magnetic field is:A) 0.288 N-m.B) 4.8 N-m.C)
Vesnalui [34]

Answer:

option (D

Explanation:

Torque is given by

torque = N x i x A x B x sinФ

where, N is number of turns, A is area, b is the magnetic field and Ф be the angle between the area vector and the magnetic field vector, i be the current.

So, torque depends on the current.

option (D)

6 0
3 years ago
How does a computer process data? *
elena55 [62]

The correct answer D: all of the above

5 0
3 years ago
An 80kg person falls 60 m off of a waterfall. What is her GPE?
ElenaW [278]

Answer:

The gravitational potential energy of the man

= mass of the man(m) × gravitational acceleration(g) × height (h)

80 Kg × 9.8 m/s^2 × 60 m

80 × 9.8 x 60 ( kg ×m^2/s^2)

47040 Joules (ans)

Hope it helps

4 0
3 years ago
A projectile was launched horizontally with a velocity of 388 m/s, 2.89 m above the ground. How long did it take the projectile
tamaranim1 [39]

Answer:

Explanation:

Given

Velocity = 388m/s

Height S = 2.89m

Required

Time

Using the equation of motion

S =ut+1/2gt²

2.89 = 388t+1/2(9.8)t²

2.89 = 388t+4.9t²

Rearrange

4.9t²+388t-2.89 =0

Factorize

t = -388±√388²-4(4.9)(2.89)/2(4.9)

t= -388±√(388²-56.644)/9.8

t = -388±387.93/9.8

t =0.073/9.8

t = 0.00744 seconds

6 0
3 years ago
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