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vitfil [10]
3 years ago
5

A circular flat coil that has N turns, encloses an area A, and carries a current i has its central axis parallel to a uniform ma

gnetic field B in which it is immersed.
The net torque on the coil is ____.


a) iBA

b) NiA

c) NiB

d) NiAB

e) Zero
Physics
1 answer:
bogdanovich [222]3 years ago
5 0

Answer:

Torque on the coil will be ZERO

Explanation:

As we know that the magnetic moment of the closed current carrying coil is always along its axis and it is given as

M = N i A

now we know that magnetic field is also along the axis of the coil so here as we know the equation of torque given as

\tau = \vec M \times \vec B

so we have

\tau = M B sin0

\tau = 0

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A 500 N force accelerates an object at 20 m s-2. What is its mass?
avanturin [10]

<u>Answer</u>: The mass of the object is 25kg.

The given question deals with Newton's second law of motion and its applications.

<u>Explanation:</u> Given force, F=500N

                                 acceleration, a=20 m/s^{2}

  From Newton's 2nd law of motion , we have

                             F=ma where m=mass of the object

                         ⇒500=m×20

                         ⇒m=500/20=25

                 ∴ Mass of the object is 25 kg .

<u> </u><u>Reference Link: </u>brainly.com/question/1141170

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8 0
2 years ago
A box of mass m = 1.80 kg is dropped from rest onto a massless, vertical spring with spring constant k = 2.00 ✕ 102 N/m that is
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Answer:

spring compressed is 0.724 m

Explanation:

given data

mass = 1.80 kg

spring constant k = 2 × 10²  N/m

initial height = 2.25 m

solution

we know from conservation of energy is

mg(h+x)  = 0.5 × k × x²       ...................1

here x is compression in spring

so put here value in equation 1 we get

1.8 × 9.8 × (2.25+x)  = 0.5 × 2× 10² × x²

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x = 0.724344

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3 years ago
Question 10 of 10
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it allows only a reduced number of electrons to flow through it.

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Explanation:

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f=m1 × a

20 = m1 ×10

20=10m1

m1=20/10

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f=m2×a

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