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IceJOKER [234]
3 years ago
8

A 4-stroke Diesel engine with a displacement of Vd = 2.5x10^-3m^3 produces a mean effective pressure of 6.4 bar at the speed of

2000 rpm. Calculate the power developed by the engine at this operating condition.
Engineering
1 answer:
yKpoI14uk [10]3 years ago
4 0

Answer:

The power developed by engine is 167.55 KW

Explanation:

Given that

V_d=2.5\times 10^{-3} m^3

Mean effective pressure = 6.4 bar

Speed = 2000 rpm

We know that power is the work done per second.

So

P=6.4\times 100\times 2.5\times 10^{-3}\times \dfrac{2\pi \times2000}{120}

We have to notice one point that we divide by 120 instead of 60, because it is a 4 cylinder engine.

P=167.55 KW

So the power developed by engine is 167.55 KW

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6 0
3 years ago
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In this exercise, you will write a Point structure that represents a space in two-dimensional space. This Point should have both
Afina-wow [57]

Answer:

Check the explanation

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Points to consider:

We need to take the input from the user

We need to find the manhatan distance and euclidian using the formula

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Manhattan:

|x_1 - x_2| + |y_1 - y_2|

Euclidian Distance:

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Code

#include<stdio.h>

#include<math.h>

struct Point{

  int x, y;

};

int manhattan(Point A, Point B){

  return abs(A.x - B.x) + abs(A.y- B.y);

}

float euclidean(Point A, Point B){

  return sqrt(pow(A.x - B.x, 2) + pow(A.y - B.y, 2));

}

int main(){

  struct Point A, B;

  printf("Enter x and Y for first point: ");

  int x, y;

  scanf("%d%d", &x, &y);

  A.x = x;

  A.y = y;

  printf("Enter x and Y for second point: ");

  scanf("%d%d", &x, &y);

  B.x = x;

  B.y = y;

  printf("Manhattan Distance: %d\n", manhattan(A, B));

  printf("Euclidian Distance: %f\n", euclidean(A, B));

 

}

Sample output

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