Explanation:
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Answer:
Explanation:
Just as context, write the chemical equation and the mole ratios
1) <u>Balanced chemical equation</u>:
- CuO (s) + H₂SO₄ (aq) → CuSO₄ (aq) + H₂O (l)
2) <u>Therotetical (stoichiometric) mole ratios</u>:
- 1 mol CuO : 1 mol H₂SO₄ : 1 mol CuSO₄ : 1 mol H₂O
You can calculate the percent yield from the amount of CuSO₄ obtained and the theoretical yield
3) <u>Percent yield</u>
Percent yield = (actual yield / theoretical yield)×100
- Theoretical yiedl (given): 3.19 moles CuSO₄
- Actual yield (given): 2.50 moles CuSO₄
Substitute the values in the formula:
- Percent yield = (2.50 moles CuSO₄ / 3.19 moles CuSO₄)×100 = 78.4%
Answer:
1 g
Explanation:
Given data:
Volume of solution = 250 mL (250 mL × 1 L/1000 mL = 0.25 L)
Molarity of solution = 0.1 M
Amount of sodium hydroxide = ?
Solution:
Molarity = number of moles / volume in L
0.1 M = number of moles /0.25 L
Number of moles = 0.1 M × 0.25 L
M = mol/ L
Number of moles = 0.025 mol
Mass of sodium hydroxide:
Mass = number of moles × molar mass
Mass = 0.025 mol ×40 g/mol
Mass = 1 g
Answer:
The answer is 3
C2H5OH + O2 CO2 +H2O (unbalanced)
C2H5OH +3O2(g). 2CO2(g)+3H2O(balanced)
