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julsineya [31]
4 years ago
8

What is the volume of a right circular cylinder with a radius of 5 cm and a height of 12 cm?

Mathematics
1 answer:
aalyn [17]4 years ago
4 0

Answer:

942.48

Step-by-step explanation:

use the formula v=bh

step 1:find base use the formula to find the area of the circle

step 2:then multiply your answer of base with your height

like this \pi5^{2}then 78.59(12)

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This equation shows how the total amount of paper Scott's office has recycled depends on the number of weeks since they started
Elodia [21]

Answer:

1 week

Step-by-step explanation:

Given:

p = 12w

Where,

w = number of weeks the office has been on the new recycling plan

p = total kilograms of paper recycled.

How many weeks will it take Scott's office to recycle a total of 12 kilograms of paper?

Find w when p = 12

p = 12w

12 = 12w

Divide both sides by 12

w = 12/12

= 1

w = 1 week

8 0
3 years ago
Which linear function represents the line given by the point slope equation y + 7= 2/3(x+6)
Andrews [41]

Hello from MrBillDoesMath!

Answer:   f(x) =   (2/3)*x -3   -- which is not a provided answer..


Discussion:


We are given that y + 7 = (2/3) * (x + 6). Multiply out the right hand side:


y + 7 = (2/3) * x + (2/3) * 6 = (2/3) *x + 12/3

        =   (2/3)*x + 4


Subtract 7 from both sides:

y + 7 - 7 = (2/3)*x + 4 - 7

or

y =  (2/3)*x -3



Thank you,

MrB


y + 7= 2/3(x+6)

7 0
3 years ago
In the right triangle shown in the diagram below,
adelina 88 [10]

QUESTION :-

what is the value of x to the nearest whole number?

ANSWER :-

\cos( \theta)  =   \frac{base}{hypotenuse}  \\  \cos(30)  =  \frac{x}{24}  \\  \frac{ \sqrt{3} }{ \cancel2}  =  \frac{x}{ \cancel{24}}  =  \frac{x}{12}  \\ 1.732 =  \frac{x}{12}  \\ 12 \times 1.732 = x \\ x = 20.7

SO

the nearest whole number-->

20.7 --> approximately --> 21 units

5 0
3 years ago
Factor 25 into prime numbers
kirill [66]

Image result for factor 25 into prime numbers

25 is a composite number, and it is 5 squared. 25 = 1 x 25 or 5 x 5. Factors of 25: 1, 5, 25. Prime factorization: 25 = 5 x 5, which can also be written 25 = 5².

8 0
4 years ago
Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the
zlopas [31]

Answer:

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}

\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

3 0
4 years ago
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