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madreJ [45]
3 years ago
13

An older-model car accelerates from 0 to speed v in a time interval of δt. a newer, more powerful sports car accelerates from 0

to 5v in the same time period. assuming the energy coming from the engine appears only as kinetic energy of the cars, compare the power of the two cars.
Physics
1 answer:
Marysya12 [62]3 years ago
8 0
Power = Energy / time = Δ kinetic energy / time = ΔKE / t

For old car: ΔKE= m(v^2) / 2 => Power = m(v^2) / (2t)


For new car: ΔKE = m (5v)^2 / 2 => Power = 25 * [ m(v^2) / (2t) ]

Then, comparing the expressions for both cars, you get that the power of the new car is 25 times the power of the old car. 
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It will sink because mass does not affect the physical properties of the object.
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( Can someone help? )
Murrr4er [49]

Answer:

Answer would be 0.33

Explanation:

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A 5.0 kg chunk of putty moving at 10m/s collides and sticks to a 7.0 kg bowling ball that is initially at rest.What is the total
Flura [38]

Answer:

Total momentum = 50kgm/s

Explanation:

<u>Given the following data;</u>

Mass, M1 = 5kg

Mass, M2 = 7kg

Velocity, V1 = 10m/s

Velocity, V2 = 0m/s (since it's at rest).

To find the total momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = Mass * Velocity

The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.

Total momentum = M1V1 + M2V2

Substituting into the equation, we have;

Total momentum = 5*10 + 7*0

Total momentum = 50 + 0

<em>Total momentum = 50 kgm/s</em>

<em>Therefore, the total momentum of the bowling ball and the putty after they collide is 50 kgm/s. </em>

8 0
3 years ago
List at least 10 derived units of some physical quantities.​
Artist 52 [7]

Answer:

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8 0
2 years ago
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In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a fur
Margaret [11]

Answer:

D = -4/7 = - 0.57

C = 17/7 = 2.43

Explanation:

We have the following two equations:

3C + 4D = 5\ --------------- eqn (1)\\2C + 5D = 2\ --------------- eqn (2)

First, we isolate C from equation (2):

2C + 5D = 2\\2C = 2 - 5D\\C = \frac{2 - 5D}{2}\ -------------- eqn(3)

using this value of C from equation (3) in equation (1):

3(\frac{2-5D}{2}) + 4D = 5\\\\\frac{6-15D}{2} + 4D = 5\\\\\frac{6-15D+8D}{2} = 5\\\\6-7D = (5)(2)\\7D = 6-10\\\\D = -\frac{4}{7}

<u>D = - 0.57</u>

Put this value in equation (3), we get:

C = \frac{2-(5)(\frac{-4}{7} )}{2}\\\\C = \frac{\frac{14+20}{7}}{2}\\\\C = \frac{34}{(7)(2)}\\\\C =  \frac{17}{7}\\

<u>C = 2.43</u>

5 0
3 years ago
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