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madreJ [45]
3 years ago
13

An older-model car accelerates from 0 to speed v in a time interval of δt. a newer, more powerful sports car accelerates from 0

to 5v in the same time period. assuming the energy coming from the engine appears only as kinetic energy of the cars, compare the power of the two cars.
Physics
1 answer:
Marysya12 [62]3 years ago
8 0
Power = Energy / time = Δ kinetic energy / time = ΔKE / t

For old car: ΔKE= m(v^2) / 2 => Power = m(v^2) / (2t)


For new car: ΔKE = m (5v)^2 / 2 => Power = 25 * [ m(v^2) / (2t) ]

Then, comparing the expressions for both cars, you get that the power of the new car is 25 times the power of the old car. 
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In a laboratory, it is often convenient to make measurements in centimeters and grams, but SI units are needed for calculations.
zheka24 [161]

Answer:

(a) 0.92 cm= 0.092 m.

(b) 141.64 g=0.14164 kg.

(c) 15. 8 cm³=0.0000158 m³

(d) 63.6 g/cm³= 63600 kg/m³

Explanation:

The International System of Units, abbreviated S.I., also called the International System of Measurements is a system of measurements in which its units are based on fundamental physical phenomena. The units of the S.I. They are the international reference for the indications of all measuring instruments.

The International System of Units (SI) arose from the need to unify and give coherence to a great variety of unit subsystems.

The International System of Units consists of seven basic units, also called fundamental units, which define the corresponding fundamental physical quantities and which allow any physical quantity to be expressed in terms or as a combination of them. The fundamental physical quantities are complemented by two more physical quantities, called supplementary ones.

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(b)  The SI unit of mass is kg. Being 1 g = 0.001 kg, then <u><em>141.64 g=0.14164 kg.</em></u>

(c) Being 1 cm³ = 0.000001 m³, then <u><em>15. 8 cm³=0.0000158 m³</em></u>

(d) Being 1 g/cm³= 1000 kg/m³, then <u><em>63.6 g/cm³= 63600 kg/m³</em></u>

3 0
3 years ago
If an arrow is shot upward on the moon with a velocity of 58 m/s, its height (in meters) after t seconds is given by H = 58t − 0
Alex73 [517]

Answer:

a) v = 54.7m/s

b) v = (58 - 1.66a) m/s

c) t = 69.9 s

d) v = -58.0 m/s

Explanation:

Given;

The height equation of the arrow;

H = 58t - 0.83t^2

(a) Find the velocity of the arrow after two seconds. m/s;

The velocity of the arrow v can be given as dH/dt, the change in height per unit time.

v = dH/dt = 58 - 2(0.83t) ......1

At t = 2 seconds

v = dH/dt = 58 - 2(0.83×2)

v = 54.7m/s

(b) Find the velocity of the arrow when t = a. m/s

Substituting t = a into equation 1

v = 58 - 2(0.83×a)

v = (58 - 1.66a) m/s

(c) When will the arrow hit the surface? (Round your answer to one decimal place.) t = s

the time when H = 0

Substituting H = 0, we have;

H = 58t - 0.83t^2 = 0

0.83t^2 = 58t

0.83t = 58

t = 58/0.83

t = 69.9 s

(d) With what velocity will the arrow hit the surface? m/s

from equation 1;

v = dH/dt = 58 - 2(0.83t)

Substituting t = 69.9s

v = 58 - 2(0.83×69.9)

v = -58.0 m/s

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Muscles that are under your conscious control are called voluntary muscles, while muscles that are not under your conscious control are called involuntary muscles

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