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Anuta_ua [19.1K]
3 years ago
9

A rocket of mass 40000kg propelled by a force of 10^6N acquires a speed of 3000m/s determine the power expended

Physics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

3×10⁹ W

Explanation:

Power = work / time

Power = force × distance / time

Power = force × velocity

P = Fv

P = (10⁶ N) (3000 m/s)

P = 3×10⁹ W

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(answer the question or get reported) Please solve it with the steps thanks :)​
DaniilM [7]

Answer:

Fx = 35.36 N

Fy = 35.36 N

Explanation:

From the question,

The X component of the force is

Fx = Fcos∅.................. Equation 1

Where Fx = X component of the force, F = Force, ∅ = Angle to the horizontal.

Give: F = 50 N, ∅ = 45°

Substitute into equation 1

Fx = 50(cos45°)

Fx = 50(0.7071)

Fx = 35.36 N

Similarly,

For Y component

Fy = Fsin∅

Where F y = Y component

Fy = 50(sin45°)

Fy = 50(0.7071)

Fy = 35.36 N

4 0
3 years ago
A parallel RLC circuit contains an inductor with a value of 400 microhenries and a capacitor with a value of 0.3 microfarads wha
ipn [44]

Answer:

The resonant frequency of this circuit is 14.5 kHz.

Explanation:

Given that,

Inductance of a parallel LCR circuit, L=400\ \mu H=400\times 10^{-6}\ H

Capacitance of parallel LCR circuit, C=0.3\ \mu F=0.3\times 10^{-6}\ F

At resonance the inductive reactance becomes equal to the capacitive reactance. The resonant frequency is given by :

f=\dfrac{1}{2\pi \sqrt{LC} }

f=\dfrac{1}{2\pi \sqrt{400\times 10^{-6}\times 0.3\times 10^{-6}} }

f=14528.79\ Hz

or

f = 14.5 kHz

So, the resonant frequency of this circuit is 14.5 kHz. Hence, this is the required solution.

4 0
3 years ago
A force F acts in the forward direction on a cart of mass m. A friction force ff opposes this motion. Part A Use Newton's second
stellarik [79]

Answer:

a = F-ff/m

Explanation:

According to Newton's second law of motion which states that "the rate of change in momentum of a body is directly proportional to the applied force F and acts in the direction of the force.

Mathematically;

F = ma

Since two forces acts on the cart i.e the moving force F and the frictional force Ff , we will take the sum of the forces.

∑F = ma where

m is the mass of the cart

a is its acceleration

∑F = F+(-ff )(since frictional force is an opposing force)

F - ff = ma

Dividing both sides by mass m

a = F-ff/m

5 0
3 years ago
PHYSICS<br> I need help with number two!!!!
EleoNora [17]

Answer:

mgh₁ + ½mv₁² = mgh₂ + ½mv₂²

Explanation:

Initial total energy = final total energy

PE₁ + KE₁ = PE₂ + KE₂

mgh₁ + ½mv₁² = mgh₂ + ½mv₂²

7 0
3 years ago
When a pair of balanced forces acts on an object, the net force that results is.
polet [3.4K]
D.  Equal to zero.

Because the forces balance each other.
7 0
3 years ago
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