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timofeeve [1]
3 years ago
12

g If a sample of 50 mL of ethyl benzene (bp = 136 C) was contaminated with 10 mL of ethyl acetate (bp = 77 C) what effect would

this have on the boiling point measurement?
Chemistry
1 answer:
PolarNik [594]3 years ago
6 0

Answer:

melting point will be higher than that of pure ethyl acetate

Explanation:

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Consider the reaction below. NH4+ + H2O mc013-1.jpg NH3 + H3O+ Which is an acid-conjugate base pair? NH4+ and NH3 NH4+ and H3O+
juin [17]
NH4+ and NH3 are an acid-conjugate base pair, since NH4+ is an acid, while NH3 is its conjugate base (since it is without the H+).
H2O and H3O+ can also be considered an acid-conjugate base pair, since H3O+ is an acid, while H2O would be its conjugate base. (But if only 1 answer is to be selected, it should be the NH4+ and NH3)
NH4+ and H3O+ are both acids, and both H2O and NH3 can be considered bases.
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3 years ago
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Geothermal energy helps to
disa [49]

Answer:A

Explanation:

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What will happen to a lighted candle that is covered by a glass jar.
Troyanec [42]
A lit candle needs to draw oxygen from the air in order to continue burning. ... Thus, oxygen inside the glass jar will decrease and it gets filled with carbon dioxide, and eventually the candle's flame will Extinguish.
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12oz of water initially at 75oF is mixed with 20oz of water intiially at 140oF. What is the final temperature?
Kaylis [27]

Answer:

115.625^{\circ}\text{F}

Explanation:

m_1 = First mass of water = 12 oz

m_2 = Second mass of water = 20 oz

\Delta T_1 = Temperature difference of the solution with respect to the first mass of water = (T-75)^{\circ}\text{F}

\Delta T_2 = Temperature difference of the solution with respect to the second mass of water = (T-75)^{\circ}\text{F}

c = Specific heat of water

As heat gain and loss in the system is equal we have

m_1c\Delta T_1=m_2c\Delta T_2\\\Rightarrow m_1\Delta T_1=m_2\Delta T_2\\\Rightarrow 12(T-75)=20(140-T)\\\Rightarrow 12T-900=2800-20T\\\Rightarrow 12T+20T=2800+900\\\Rightarrow 32T=3700\\\Rightarrow T=\dfrac{3700}{32}\\\Rightarrow T=115.625^{\circ}\text{F}

The final temperature of the solution is 115.625^{\circ}\text{F}.

3 0
3 years ago
A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the pressure is increased to 1.25 atm. (Boyle)
vlabodo [156]

Answer:

<h2>2.60 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{4.31 \times 0.755}{1.25}  =  \frac{3.25405}{1.25}  \\  = 2.60324

We have the final answer as

<h3>2.60 L</h3>

Hope this helps you

6 0
3 years ago
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