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Arisa [49]
3 years ago
13

Which occurs when two musical instruments use resonance?

Physics
2 answers:
polet [3.4K]3 years ago
8 0
D, they are both loud
likoan [24]3 years ago
5 0
D). they are both loud
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a body starts from rest with a uniform acceleration of 2m s-2 find the distance covered by the body in 2s
Evgen [1.6K]
Finding acceleration= final velocity-initial velocity/ time taken (or A= V-U/T)

Final speed= 2m
Initial speed= 0m
Time taken= 2 seconds

2-0/2 so it’ll be 1m/s

2-0=0
2/2=

8 0
3 years ago
Convert -13°F into (a) °C (b) kelvin​
RideAnS [48]

Answer:

-25ºC

Explanation:

3 0
2 years ago
Professional Application: A 30,000-kg freight car is coasting at 0.850 m/s with negligible friction under a hopper that dumps 11
Nataliya [291]

Answer:

0.182 m/s

Explanation:

m1 = 30,000 kg, m2 = 110,000 kg, u1 = 0.85 m/s

let the velocity of loaded freight car is v

Use the conservation of momentum

m1 x u1 + m2 x 0 = (m1 + m2) x v

30,000 x 0.85 = (30,000 + 110,000) x v

v = 0.182 m/s

5 0
3 years ago
One cycle of the power dissipated by a resistor ( R = 800 Ω R=800 Ω) is given by P ( t ) = 60 W , 0 ≤ t < 5.0 s P(t)=60 W, 0≤
OLga [1]

Answer:

42.5W

Explanation:

To solve this problem we must go back to the calculations of a weighted average based on the time elapsed thus,

Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}

We need to calculate the average power dissipated by the 800\Omega resistor.

Our values are given by:

P(t)=60 W, 0\leq t

P(t)=25 W, 5.0\leq t

Aplying the values to the equation we have:

Power_{avg} = \frac{P_1(t_1)+P_2(t_2)}{t_1+t_2}

Power_{avg} = \frac{60(5-0)+25(10-5)}{(5-0)+(10-5)}

Power_{avg} = 42.5W

5 0
3 years ago
An increase in resistance causes the flow of electric current to
Zolol [24]

An increase in voltage causes the flow of electric current to INCREASE. An increase in resistance causes the flow of electric current to DECREASE.

100% right

6 0
3 years ago
Read 2 more answers
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